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Pachacha [2.7K]
3 years ago
13

Please Help! 13. List all of the elements of each seta) Set of integer solutions of x^2≤3

Mathematics
1 answer:
adell [148]3 years ago
4 0

Answer:

S = {-1, 0, 1}

Step-by-step explanation:

First we need to solve the inequation x^2<=3

Using square root in both sides, we have:

|x| <= 1.73

Separating the module in two, we have:

x <= 1.73

x >= 1.73

So we have that -1.73 <= x <= 1.73

Solving this inequation only with integer values, we have:

x = -1, x = 0 or x = 1

So the set of integer solutions is S = {-1, 0, 1}

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Given the coordinates below, what is the midpoint of AB?<br> A(-6, -10)<br> B(2,5)
madreJ [45]

Given :

\:

  • A(-6, -10)
  • B( 2, 5)

\:

\gray{ \frak{The \:  given \:  two \:   \: points  \: are(x_{1 },y_{1})=(−6 , -10)and(x_{ 2 },y_{2} )=( 2,5 )\:}}

\:

Let's solve by using midpoint formula :

\:

\bf \boxed{\color{red}\frak{Midpoint \:   \: Formula :  {( \: x ,\:y \:  ) = }(  \frak{ \frac{x_{1 } + y_{1}}{2} , \frac{x_{2 } + y_{2}}{2} )}}}

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\large \gray{ \frak{( \: x ,\:y \:  ) = }(  \frak{ \frac{ -6 + 2}{2} , \frac{ - 10 + 5}{2} )}}

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\: \large \gray{ \frak{( \: x ,\:y \:  ) = }(  \frak{ \frac{ -4}{2} , \frac{ - 5}{2} )}}

\:

\large \gray{ \frak{( \: x ,\:y \:  ) = }(  \frak{  \cancel\frac{ -4}{2} ,  \cancel\frac{ - 5}{2} )}}

\:  \:

\underline{ \boxed{ \large \red{ \frak{option \: d }(  \frak{   - 2, - 2.5)}}}}✓

Hope Helps! :)

6 0
2 years ago
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