The area of a circle is pi times the radius squared (A = π r²).
Answer:
B: -16
Step-by-step explanation:
Plug the variables in accordingly. 3(-2)(4)+2(4)
-6(4)+8
-24+8
-16
Answer:
Yes, A KLP can be reflected across the line containing KP and then translated so that Pis mapped to M.
Step-by-step explanation:
The figure shows two congruent by HA theorem (they have congruent hypotenuses and a pair of congruent angles adjacent to the hypotenuses) triangles KLP and QNM.
A rigid transformation is a transformation which preserves lengths. Reflection, rotation and translation are rigit transformations.
If you reflect triangle KLP across the leg KP and translate it up so that point P coincides with point M , then the image of triangle KLP after these transformations will be triangle QNM.
Unfortunately, Tashara, you have not provided enuf info from which to calculate the values of a and b. If you were to set <span>F(x)=x(x+a)(x-b) = to 0, then:
x=0,
x=-a
x=-b
but this doesn't answer your question.
Double check that you have shared all aspects of this question.</span>
Answer:
-12
Step-by-step explanation:
Let the number be A
Given if you divide the sum of six and the number A by 3 , the result is 4 more than 1/4 of A
That’s
6+A/3 = 4+1/4 of A
6+A/3 = 4+1/4 x A
6+A/3 = 4+A/4
Cross multiply
4(6 + A) = 3(4 + A)
Distribute
4 x 6 + 4 x A = 3 x 4 + 3 x A
24 + 4A = 12 + 3A
Subtract 24 from both sides to eliminate 24 on the left side
24 - 24 + 4A = 12 - 24 + 3A
4A = -12 + 3A
Subtract 3A from both sides so the unknown can be on one side
4A - 3A = -12 + 3A - 3A
A = -12
Check
6+(-12)/3 = 4 +(-12)/4
6 -12/3 = 4 -12/4
-6/3 = -8/4
-2 = -2
