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just olya [345]
3 years ago
14

In a factory, 3.25% of the jars of peanut butter produced contains less peanut butter than is advertised on the label. The facto

ry produces 1200 jars of peanut butter every hour. In three 8- hour work days, how many jars of peanut butter do you expect to contain less peanut butter than usual?
Mathematics
1 answer:
marshall27 [118]3 years ago
7 0

Answer:

936 jars of peanut butter contain less peanut butter than usual.

Step-by-step explanation:

1. First, we need to find how many jars of peanut butter that contain less peanut butter than advertised are produced every hour.

The factory produces 1200 jars of peanut butter every hour

3.25% of those jars have less peanut butter than advertised

So: multiply (1200*.0325) (the decimal form of the percent) to find the amount of peanut butter jars that contain less peanut butter than advertised.

(1200*.0325) = 39

So the factory produces 39 jars of peanut butter that contain less peanut butter than advertised.

2. Second, we need to find how many jars of peanut butter that contain less peanut butter than advertised in three 8 hour work days.

Lets add these work days together to find the total amount of hours: (8 + 8 + 8) = 24

So: three 8 hour work days totals to 24 hours

Since the factory produces 39 jars of peanut butter that contain less peanut butter than advertised per hour. Multiply (24 * 39) to find the total amount of jars produced in three 8 hour work days.

(24 *39) = 936

A total of 936 peanut butter jars are produced in three 8 hour work days that contain less peanut butter than advertised.

3. If you want to double check your work do the following.

Since the factory produces 1200 jars an hour and 24 hours total three 8 hour work days. Multiply (1200*24) = 28800

So there is a total of 28800 jars produced in three 8 hour work days.

Then you can multiply 28800 by 3.25% of jars that contain less peanut butter to find the total amount of peanut butter jars that contain less peanut butter in three 8 hour work days.

(28800 * .0325) = 936

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Answer:

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Step-by-step explanation:

We know this because the proportion can be used to find another answer.

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How many feet did the elevator ascend in 0.25 minutes?

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750(0.25) = 1x

187.5 = x

***Sorry about the format. Hope this helps!

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40x + 60 = 20. what does x equal?
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Subtract 60 on both sides to get -40.

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Determine whether the equation is exact. If it​ is, then solve it. e Superscript t Baseline (7 y minus 3 t )dt plus (2 plus 7 e
umka21 [38]

Answer:

F(t,y)=(2+7e^t)y+3(1-t)e^t +C

Step-by-step explanation:

You have the following differential equation:

e^t(7y-3t)dt+(2+7e^t)dy=0

This equation can be written as:

Mdt+Ndy=0

where

M=e^t(7y-3t)\\\\N=(2+7e^t)

If the differential equation is exact, it is necessary the following:

\frac{\partial M}{\partial y}=\frac{\partial N}{\partial t}

Then, you evaluate the partial derivatives:

\frac{\partial M}{\partial y}=\frac{\partial}{\partial t}e^t(7y-3t)\\\\\frac{\partial M}{\partial t}=7e^t\\\\\frac{\partial N}{\partial t}=\frac{\partial}{\partial t}(2+7e^t)\\\\\frac{\partial N}{\partial t}=7e^t\\\\\frac{\partial M}{\partial t} = \frac{\partial N}{\partial t}

The partial derivatives are equal, then, the differential equation is exact.

In order to obtain the solution of the equation you first integrate M or N:

F(t,y)=\int N \partial y = (2 +7e^t)y+g(t)        (1)

Next, you derive the last equation respect to t:

\frac{\partial F(t,y)}{\partial t}=7ye^t+g'(t)

however, the last derivative must be equal to M. From there you can calculate g(t):

\frac{\partial F(t,y)}{\partial t}=M=(7y-3t)e^t=7ye^t+g'(t)\\\\g'(t)=-3te^t\\\\g(t)=-3\int te^tdt=-3[te^t-\int e^tdt]=-3[te^t-e^t]

Hence, by replacing g(t) in the expression (1) for F(t,y) you obtain:

F(t,y)=(2+7e^t)y+3(1-t)e^t +C

where C is the constant of integration

8 0
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