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elena-14-01-66 [18.8K]
3 years ago
5

Metric conversions

Physics
1 answer:
sergij07 [2.7K]3 years ago
7 0

1:-

  • 1L=1000mL

\\ \sf\longmapsto 45.23L

\\ \sf\longmapsto 45.23\times 1000

\\ \sf\longmapsto 45230mL

2:-

  • 1hL=10000cL

\\ \sf\longmapsto .035hL

\\ \sf\longmapsto 0.035\times 10000

\\ \sf\longmapsto 350cL

3:-

  • 1mm=0.0001m

\\ \sf\longmapsto 27.32

\\ \sf\longmapsto 27.32\times 0.0001

\\ \sf\longmapsto 0.0027m

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The work done on the car is -20 J.

Work done on the car is negative, meaning that the car actually does work on the external system.

<h3>Energy and law of conservation of energy</h3>
  • Energy is the ability to do work
  • the law of conservation of energy states that the total energy in a system is conserved

From the law of conservation of energy, the initial energy of the car before it moves down the road remains constant or unchanged.

  • Initial energy = 100 J
  • Initial energy = Final energy - work done on car
  • Final Energy = Work done on car + initial energy

80J = Work done on car + 100 J

Work done on car = 80 - 100J

Work done on car = -20 J

Hence, the work done on the car is -20 J

Work done on car is negative.

Since work done on the car is negative, it means that the car actually does work on the external system. Hence, the decrease in the energy of the car.

Learn more about energy and work at: brainly.com/question/13387946

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What quantity does a Percent measure?
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In mathematics, a percentage is a number or ratio expressed as a fraction of 100.

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<h3>Hope this helps </h3>
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Consider an insulating sphere of radius 6 cm surrounded by a conducting sphere of inner radius 18 cm and outer radius 26 cm. Fur
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Answer:

-1.7908787542\times 10^{-9}\ C

3.4260289211\times 10^{-9}\ C

1.7908787542\times 10^{-9}\ C

1.6351501669\times 10^{-9}\ C

Explanation:

r = Radius

k = Coulomb constant = 8.99\times 10^{9}\ Nm^2/C^2

Electric field is given by

E=-\dfrac{kq}{r^2}\\\Rightarrow q=-\dfrac{Er^2}{k}\\\Rightarrow q=-\dfrac{1610\times 0.1^2}{8.99\times 10^9}\\\Rightarrow q=-1.7908787542\times 10^{-9}\ C

The charge is -1.7908787542\times 10^{-9}\ C

Q+q=\dfrac{Er^2}{k}\\\Rightarrow Q=\dfrac{Er^2}{k}-q\\\Rightarrow Q=\dfrac{120\times 0.35^2}{8.99\times 10^9}-(-1.7908787542\times 10^{-9})\\\Rightarrow Q=3.4260289211\times 10^{-9}\ C

The charge is 3.4260289211\times 10^{-9}\ C

The charge inside will have the polarity changed

q=+1.7908787542\times 10^{-9}\ C

Outside the charge will be

3.4260289211\times 10^{-9}-1.7908787542\times 10^{-9}\\ =1.6351501669\times 10^{-9}\ C

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The acceleration due to gravity of the planet X is 1 m/s².

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The acceleration due to gravity is calculated as follows;

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Thus, the acceleration due to gravity of the planet X is 1 m/s²

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