All categories

3 years ago

Metric conversions

Physics

1 answer:

sergij07 [2.7K]3 years ago

7 0

1:-

1L=1000mL

$\\ \sf\longmapsto 45.23L$

$\\ \sf\longmapsto 45.23\times 1000$

$\\ \sf\longmapsto 45230mL$

2:-

1hL=10000cL

$\\ \sf\longmapsto .035hL$

$\\ \sf\longmapsto 0.035\times 10000$

$\\ \sf\longmapsto 350cL$

3:-

1mm=0.0001m

$\\ \sf\longmapsto 27.32$

$\\ \sf\longmapsto 27.32\times 0.0001$

$\\ \sf\longmapsto 0.0027m$

You might be interested in

Which of the following best describes the role of attention from a caregiver on the development of intelligence?

WINSTONCH [101]

A child's IQ may increase with attention from a caregiver" is the one among the following that best describes the role of attention from a caregiver on the development of intelligence. The correct option among all the options that are given in the question is the first option. I hope the answer has helped you.

8 0

3 years ago

Read 2 more answers

3. What is the potential energy of a 8 Newton book sitting on a shelf that is 12 meters high?

Svetradugi [14.3K]

Answer:

P = 96 J

Explanation:

Given that,

Weight of the book, W = mg = 8 N

It is placed at a height of 12 m

We need to find the potential energy of the book. The potential energy of an object is given by the formula as follows :

E = mgh

mg = Weight

$E=8\ N\times 12\ m\\E=96\ J$

So, the potential energy of the book is 96 J.

8 0

3 years ago

A train increase its speed steadily from 10m/s to 20m/s in 1minutes A what is the average speed during this time in m/s B how fa

Ipatiy [6.2K]

If it increased its speed steadily at a constant rate, then the average speed for the minute was

(1/2)(10m/s + 20m/s) = 15 m/s .

Rolling at an average speed of 15 m/s for 1 minute (60 seconds), it travels

(15 m/s) (60 sec) = 900 meters

3 0

3 years ago

A 2.93 kg particle has a velocity of (2.98 i hat - 3.98 j) m/s.

cupoosta [38]

Answer:

a) The x and y components of the momentum are $8.731\,\frac{kg\cdot m}{s}$ and $-11.661\,\frac{kg\cdot m}{s}$ , respectively.

b) The magnitude and direction of its momentum are approximately 14.567 kilogram-meters per second and 306.823º.

Explanation:

a) The vectorial equation of momentum is represented by the following expression:

$\vec p = m\cdot \vec v$ (1)

Where:

$\vec p$ - Vector momentum, measured in kilogram-meters per second.

$m$ - Mass of the particle, measured in kilograms.

$\vec v$ - Vector velocity, measured in meters per second.

If we know that $m = 2.93\,kg$ and $\vec v = 2.98\,\hat{i}-3.98\,\hat{j}\,\,\,\left[\frac{m}{s} \right]$ , then the momentum is:

$\vec p = (2.93)\cdot (2.98\,\hat{i}-3.98\,\hat{j})\,\,\,\left[\frac{kg\cdot m}{s} \right]$

$\vec p = 8.731\,\hat{i}-11.661\,\hat{j}\,\,\,\left[\frac{kg\cdot m}{s} \right]$

The x and y components of the momentum are $8.731\,\frac{kg\cdot m}{s}$ and $-11.661\,\frac{kg\cdot m}{s}$ , respectively.

b) The magnitude and direction of momentum are represented by the following expressions:

$\|\vec p \| = \sqrt{p_{x}^{2}+p_{y}^{2}}$ (2)

$\theta = \tan^{-1}\left(\frac{p_{y}}{p_{x}} \right)$ (3)

Where:

$\|\vec p\|$ - Magnitude of momentum, measured in kilogram-meters per second.

$\theta$ - Direction of momentum, measured in sexagesimal degrees.

If we know that $p_{x} = 8.731\,\frac{kg\cdot m}{s}$ and $p_{y} = -11.661\,\frac{kg\cdot m}{s}$ , then the magnitude and direction of momentum are, respectively: