True its very important to do those things
Answer:
Correct answer: Fg = m · g
Explanation:
Newton's second law states that if a resultant force is applied to an object, the object begins to move at an accelerated rate.
The formula that presents this is:
F = m · a
this formula applies to an object moving on some surface
where m is the mass of the object and a the acceleration of the object
Let's take it now and watch the free fall:
The formula that presents this is:
Fg = m · g
this formula applies to an object moving at free fall in vertical direction
Free fall is also an accelerated movement to which Newton's second law applies.
where m is the mass of the object and g the gravitation acceleration of the object . We also know that g is equal:
g = γ · Me / d² where Me is mass of the earth
God is with you!!!
A microwave uses heat waves that keeps in side the machine to heat up the cup of water
Hope this helps :)
To develop this problem we will start using the concept of maximum speed for this type of systems. The maximum velocity can be described as the product between the Amplitude and the Angular velocity. At the same time, said angular velocity can be found through the relationship between linear and "angular wavenumber" velocity. The Angular wavenumber is a wave number defined as the number of radians per unit distance. Finally with the value of the angular velocity found we will proceed to find the maximum speed.
The maximum speed is given by
![v_{max} = A\omega](https://tex.z-dn.net/?f=v_%7Bmax%7D%20%3D%20A%5Comega)
Here,
A = Amplitude
= Angular velocity
The angular velocity can be described as the number of radians per unit distance
![\omega = vk](https://tex.z-dn.net/?f=%5Comega%20%3D%20vk)
![\omega = v (\frac{2\pi}{\lambda})](https://tex.z-dn.net/?f=%5Comega%20%3D%20v%20%28%5Cfrac%7B2%5Cpi%7D%7B%5Clambda%7D%29)
![\omega = 112(\frac{2\pi}{12.16})](https://tex.z-dn.net/?f=%5Comega%20%3D%20112%28%5Cfrac%7B2%5Cpi%7D%7B12.16%7D%29)
![\omega =57.8714rad/s](https://tex.z-dn.net/?f=%5Comega%20%3D57.8714rad%2Fs)
Then,
![v_{max} = 0.12 *57.8714](https://tex.z-dn.net/?f=v_%7Bmax%7D%20%3D%200.12%20%2A57.8714)
![v_{max} = 6.94m/s](https://tex.z-dn.net/?f=v_%7Bmax%7D%20%3D%206.94m%2Fs)
Therefore the maximum speed a point on the medium moves as this wave passes is 6.94m/s