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4 years ago

Physics 1 Course. please help.

Physics

1 answer:

Aleks [24]4 years ago

6 0

Answer:

a. 1.64 m/s²

Explanation:

Centripetal acceleration is the square of tangential velocity divided by the radius.

a = v²/r

First, convert km/h to m/s.

30.0 km/h (1000 m/km) (1 h / 3600 s) = 8.33 m/s

Find the acceleration.

a = (8.33 m/s)² / (42.4 m)

a = 1.64 m/s²

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4 years ago

An aluminum wire is held between two clamps under zero tension at room temperature. Reducing the temperature, which results in a

Blababa [14]

Answer:

$\frac{\Delta L}{L} =5.37\times 10^{-4}$

Explanation:

Given:

cross sectional area of the wire, $A=5.75\times 10^{-6}\ m^2$

density of aluminium wire, $\rho=2.7\times 10^3\ kg.m^{-3}$

young's modulus of the material, $E=7\times 10^{10}\ N.m^{-2}$

wave speed, $v=118\ m.s^{-1}$

We have mathematical expression for strain as:

$\frac{\Delta L}{L} =\frac{\sigma}{E}$ ...............................(1)

and since, $\sigma =\frac{T}{A}$

where, T = tension force in the wire

equation (1) becomes:

$\frac{\Delta L}{L} =\frac{T}{A.E}$ ............................(2)

Also velocity ofwave in tensed wire:

$v=\sqrt{\frac{T}{\mu} }$ ...................................(3)

where: $\mu=$ linear mass density of the wire

$\therefore \mu=\rho \times A$

Now, equation (3) becomes

$v=\sqrt{\frac{T}{\rho \times A} }$

$T=v^2.\rho \times A$ ............................(4)

Using eq. (2) & (4) for tension T

$v^2.\rho \times A=A.E\times \frac{\Delta L}{L}$

$\frac{\Delta L}{L} =\frac{v^2.\rho}{E}$

putting the respective values

$\frac{\Delta L}{L} =\frac{118^2\times 2.7\times 10^3}{7\times 10^{10}}$

$\frac{\Delta L}{L} =5.37\times 10^{-4}$

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Answer:

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Explanation:

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3 years ago

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Answer:

Explanation:

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2.The forces the objects exert on each other are internal to the system and don't change the total momentum of the system.

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3 years ago

Physics 1 Course. please help. ​

Physics 1 Course. please help.