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Allushta [10]
3 years ago
5

Find the general solution to the homogeneous differential equation:

Mathematics
1 answer:
arsen [322]3 years ago
8 0

Answer:

r_{1} = -6, r_{2} = -4

Step-by-step explanation:

r_{1} and r_{2} are the eingenvalues of the equation, that is

the values of r when

r^{2} + 10r + 24 = 0

Using r = (dy/dt).

They are

r = -6, r = -4

r2 is larger than r1, so

r_{1} = -6, r_{2} = -4

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Which expression is equivalent to (4x+11)+7x answers: /1. 22x /2. (4x+7x)+11 /3. (4x+11x)+7 /4. (4x-7x)+11
lions [1.4K]
In this question the brackets aren't really necessary

so (4x + 11) + 7x is the same as 4x + 11 + 7x

so find an answer that has the same 3 terms, but just rearranged with brackets
6 0
3 years ago
g in october 2012, apple introduced a much smaller version of the apple ipad, known as the ipad mini. weighing less than 11 ounc
atroni [7]

Using the concepts of probability, we got that 0.4286 is the probability  that the battery life for an iPad Mini will be 10 hours or less  which is about 42.86%.

From the given information;

Let  X represent the continuous random variable with uniform distribution U (A, B) . Therefore the probability density function can now be determined as :

f_X(x) = \frac{1}{B-A} where A<x<B

where A and B  are the two parameters of the uniform distribution

From the question;

Assume that battery life of the iPad Mini is uniformly distributed between 8.5 and 12 hours

So; Let A = 8,5 and B = 12

Therefore; the mathematical expression for the probability density function of battery life is :

f_X(x) = [1 / (12-8.5)]8.5<x<12

f_X(x)=(1/3.5)8.5<x<12

The  probability that the battery life for an iPad Mini will be 10 hours or less can be calculated as:

F(x) = P(X ≤x)

F(10)=(x-A)/(B-A)

F(10)=(10-8.5)/(12-8.5)

F(10)=1.5/3.5

F(10)=0.4286

Hence, the probability that the battery life for an iPad Mini will be 10 hours or less is 0.4286

To know more about probability, visit here:

brainly.com/question/11234923?

#SPJ4

(Complete question)

In October of 2012, Apple introduced a much smaller variant of the Apple iPad, known at the iPad Mini. Weighing less than 11 ounces, it was about 50% lighter than the standard iPad. Battery tests for the iPad Mini showed a mean life of 10.25 hours (The Wall Street Journal, October 31, 2012). Assume that battery life of the iPad Mini is uniformly distributed between 8.5 and 12 hours. What is the probability that the battery life for an iPad Mini will be 10 hours or less (to 4 decimals)?

8 0
1 year ago
I NEED HELPP MY EXAM
s2008m [1.1K]

Answer:

Exam??

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The probability that a randomly selected 2 2​-year-old male garter snake garter snake will live to be 3 3 years old is 0.98861 0
Mnenie [13.5K]

Answer:

a. Probability = 0.97735

b. Probability = 0.92294

c. P(At\ Least\ One) = 1

No, it is not unusual if at least 1 lives up to 3.

Step-by-step explanation:

Given

Represent the probability that a 2 year old snake will live to 3 with P(Live);

P(Live) = 0.98861

Solving (a): Probability that two selected will live to 3 years.

Both snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)\ and\ P(Live)

Probability = 0.98861 * 0.98861

Probability = 0.9773497321

Probability = 0.97735 <em>--- Approximated</em>

Solving (b): Probability that seven selected will live to 3 years.

All 7 snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)^n

Where n = 7

Probability = 0.98861^7

Probability = 0.92294324145

Probability = 0.92294 <em>--- Approximated</em>

Solving (c): Probability that at least one of seven selected will not live to 3 years.

In probabilities, the following relationship exist:

P(At\ Least\ One) = 1 - P(None).

So, first we need to calculate the probability that none of the 7 lived up to 3.

If the probability that one lived up to 3 years is 0.98861, then the probability than one do not live up to 3 years is 1 - 0.98861

This gives:

P(Not\ Live) = 0.01139

The probability that none of the 7 lives up to 3 is:

P(None) = P(Not\ Live)^7

P(None) = 0.01139^7

Substitute this value for P(None) in

P(At\ Least\ One) = 1 - P(None).

P(At\ Least\ One) = 1 - 0.01139^7

P(At\ Least\ One) = 0.99999999999997513055642436060443621

P(At\ Least\ One) = 1 ---- Approximated

No, it is not unusual if at least 1 lives up to 3.

This is so because the above results, which is 1 shows that it is very likely for at least one of the seven to live up to 3 years

7 0
3 years ago
The numbers that were rounded to the nearest tenth and hundredth are missing. Complete the table to show what numbers could have
Archy [21]
Answers:
2.628
5.473
3.853
7 0
3 years ago
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