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choli [55]
3 years ago
14

What are some uses we might have for standing waves?​

Chemistry
1 answer:
VARVARA [1.3K]3 years ago
5 0
Any waves traveling along the medium will reflect back when they reach the end.
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Click the "draw structure" button to launch the drawing utility. under certain reaction conditions, 2,3−dibromobutane reacts wit
REY [17]

Answer:

Explanation:

According to this. Let's analize the possible products a, b and c.

First, the problem states that we have 2 eq. of base, For this case, let's assume it's KOH. Now, As we are doing a reaction with base, means that this reaction can only take places under conditions of SN2 and E2, a fast reaction that is taking place in only 1 step.

With this in mind, let's analyze product a. This states that it has two sp hybridized carbon, in other words, a triple bond between two carbons. So the product is with no doubt, an alkyne.

Product b has only one sp hybridized carbon, which means that this carbon should cannot be an alkyne because we need two carbon atoms. The only way to have one atom of C sp hybridized, is with two double bonds, so product b would have to a alkene with two double bonds.

Product c do not have sp hybridized carbon, therefore, it only has two double bonds in two different Carbon atoms, so it's another alkene with two double bonds, but in two different atoms of carbon.

Picture attached show the product a, b and c. Hope this can help

4 0
3 years ago
Solve pls brainliest
sammy [17]

Answer:

Even though the two substances possess many similarities, they have some unique properties. In turn, since they have the same properties, if they were the same substance, it would make matters worse, if the same chemical was in two different places, there would not be a difference between them since they are the same, just as it is with are two different chemicals would have differing properties since they are two properties would vary from one another since they are 2 totally different things!

4 0
2 years ago
Calculate the mass percent of calcium chloride in 8.87 g of calcium chloride in 65.1 g of water
zhannawk [14.2K]

Answer:

11.99 % ≅ 12.0%.

Explanation:

∵ mass % = [mass of solute/mass of solution] x 100.

mass of solute (CaCl₂) = 8.87 g & mass of solution = 8.87 g + 65.1 g = 73.97 g.

<em>∴ mass % of (CaCl₂) = [mass of solute/mass of solution] x 100 </em>= ( 8.87 g/ 73.97 g) x 100 = <em>11.99 % ≅ 12.0%.</em>

7 0
3 years ago
You have 125 g of a certain seasoning and are told that it contains 70.0 g of salt. What is the peroentage of salt by mass in th
Ket [755]

\frac{70}{125}  \times 100 = 56\%
6 0
3 years ago
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If the temperature of an area drops 8 degrees from one day the next the climate has changed.
vlabodo [156]
I would say false hope that helped
3 0
3 years ago
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