Answer:
Answer of question a is 345J.
Explanation:
In question a following is given in data:
-mass of iron (m) = 10.0 g
-temperature (ΔT) = final temperature- initial temperature= 100-25= 75 degree Celsius
-Specific Heat capacity of iron (c)= 0.46J/g°C.
Heat (Q)=?
Solution:
Formula for Heat is :
Q=m x c x ΔT
Q= 10 x 0.46 x 75
Q= 345 J.
so, 345 joules of heat is needed to increase the temperature of 10 grams of iron.
- From the above formula all other questions can easily be solved from the same procedure.
You have to start listing from the bottom :
3. Secondary Consumers
2. Primary Consumers
1. Producer
Answer:
Option A
Explanation:
They are portable resources that convert chemical energy to electrical energy
Answer:
Formation of a precipitate
Explanation:
- A precipitate is a compound in solid-state that is formed when two soluble or aqueous compounds or salts react during a precipitation reaction.
- Precipitation reaction involves a reaction between two soluble salts or compounds to form a precipitate and an aqueous compound.
- For instance, a reaction between potassium chloride and silver nitrate is a precipitation reaction.
KCl(aq) + AgNO₃(aq) → KNO₃(aq) + AgCl(s)
- All the other choices are indicators of a chemical reaction or a chemical change.
The physical property you measured is the boiling point of the liquid.
Therfore, if the liquid has a boiling point of 100°C, it turns from liquid state to vapor when you heat it up to 100°C.
To conclude, The liquid should be pure water. Because only pure water has a boiling point of 100°C, using this physical property, we can test whatever liquid ans see if it's pure water or not, this test is called the boiling point test.
