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Hunter-Best [27]
3 years ago
11

Choose which statements correctly identify the relationship of mass, volume, and density by clicking the sentence.

Chemistry
2 answers:
erica [24]3 years ago
8 0

Explanation:

It is known that density is defined as mass divided by volume occupied by the object.

Mathematically,     Density = \frac{mass}{volume}

So, density is directly proportional to mass but density is inversely proportional to volume of a substance or object.

Therefore, with decrease in volume and increase in mass there will occur an increase in density of the substance.

Thus, we can conclude that following given statements are correct.

  • Density increases if the volume of an object decrease and the mass remains the same.
  • Density increases if the mass of an object increases and the volume remains the same.
  • Density remains the same if the mass and volume of an object increases proportionally.
LenaWriter [7]3 years ago
4 0

Answer:

Density increases if the volume of an object decrease and the mass remains the same.    true

Density decreases if the mass and volume of an object decrease proportionally.      True

Explanation:

only false statement If the volume of an object increases and the mass remains the same, then density increases

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A certain liquid X has a normal freezing point of 7.60 °C and a freezing point depression constant K= 6.90 °C-kg-mol. Calculate
Dmitry [639]

<u>Answer:</u> The freezing point of solution is -5.11°C

<u>Explanation:</u>

Vant hoff factor for ionic solute is the number of ions that are present in a solution. The equation for the ionization of sodium chloride follows:

NaCl(aq.)\rightarrow Na^{+}(aq.)+Cl^-(aq.)

The total number of ions present in the solution are 2.

To calculate the molality of solution, we use the equation:

Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

Where,

m_{solute} = Given mass of solute (NaCl) = 7.57 g

M_{solute} = Molar mass of solute (NaCl) = 58.44 g/mol

W_{solvent} = Mass of solvent (liquid X) = 350.0 g

Putting values in above equation, we get:

\text{Molality of }NaCl=\frac{7.57\times 1000}{58.44\times 350.0}\\\\\text{Molality of }NaCl=0.370m

To calculate the depression in freezing point, we use the equation:

\Delta T=iK_fm

where,

i = Vant hoff factor = 2

K_f = molal freezing point depression constant = 6.90°C/m

m = molality of solution = 0.370 m

Putting values in above equation, we get:

\Delta T=2\times 6.90^oC/m.g\times 0.370m\\\\\Delta T=5.11^oC

Depression in freezing point is defined as the difference in the freezing point of water and freezing point of solution.

\Delta T=\text{freezing point of water}-\text{freezing point of solution}

\Delta T = 5.11 °C

Freezing point of water = 0°C

Freezing point of solution = ?

Putting values in above equation, we get:

5.106^oC=0^oC-\text{Freezing point of solution}\\\\\text{Freezing point of solution}=-5.11^oC

Hence, the freezing point of solution is -5.11°C

7 0
4 years ago
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