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Serjik [45]
3 years ago
7

You are sitting outside on a warm day with a cold glass of water. You notice water droplets starting to collect on the outside o

f the glass. What kind of phase change are you observing?
1.Melting
2.Condensation
3.Evaporation
4.Sweating
Chemistry
2 answers:
stellarik [79]3 years ago
7 0
The answer is 2

No explanation needed
Katarina [22]3 years ago
3 0

Answer:

2

Explanation:

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1.....What are the 2 major divisions of Biochemistry?
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Organic and inorganic

Explanation:

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2 years ago
g Calculate the [OH-] from the results of your titrations. Explain your calculations2. Calculate the [Ca2+]. Explain your calcul
RideAnS [48]

Answer:

Explanation:

*Since the titration is between the strong acid HCl and the strong base Ca(OH)2, the pH at the equivalent point should be 7. On interpolation, we will obtain that 9.50mL and 9.82 mL of HCl is required to completely neutralized the given Ca(OH)2 solution.

*pH at the equivalence point =7

we know that pH + pOH = 14

Hence pOH= 14-7=7

pOH= -log(OH-)

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3 years ago
18. Focal length is a length which lies between
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Answer:

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7 0
3 years ago
if 0.0203 g of a gas dissolves in 1.39 l of water at 1.02 atmospheres at what pressure (in atm) would you be able to dissolve 0.
Sergeu [11.5K]
First, we need to get n1 (no.of moles of water ): when

mass of water = 0.0203 g and the volume = 1.39 L

∴ n1 = mass / molar mass of water

        = 0.0203g / 18 g/mol
        = 0.00113 moles

then we need to get n2 (no of moles of water) after the mass has changed:

when the mass of water = 0.146 g

n2 = mass / molar mass

     = 0.146g / 18 g/ mol
     = 0.008 moles

so by using the ideal gas formula and when the volume is not changed:

So, P1/n1 = P2/n2 

when we have P1 = 1.02 atm 

and n1= 0.00113 moles

and n2 = 0.008 moles 

so we solve for P2 and get the pressure

∴P2 = P1*n2 / n1

        =1.02 atm *0.008 moles / 0.00113 moles

       = 7.22 atm

∴the new pressure will be 7.22 atm


5 0
3 years ago
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