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amid [387]
3 years ago
11

If I have 5.6 liters of gas in a piston at a pressure of 150 kPa and compress the gas until its volume is 4.8 L, what will the n

ew pressure inside the piston be? round to 2 decimal places
Chemistry
1 answer:
Mashcka [7]3 years ago
6 0

Answer:

P1V1 = P2V2

(1.5 atm)(5.6 L) = (x)(4.8 L) x = 1.8 atm

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Answer:

they all have different chemical compositions from earth

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earth is filled more with oxygen and nitrogen

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6 0
4 years ago
The combustion reaction described in part (b) occurred in a closed room containing 5.56 10g of air
vagabundo [1.1K]

Answer:

Explanation:

Combustion reaction is given below,

C₂H₅OH(l) + 3O₂(g) ⇒ 2CO₂(g) + 3H₂O(g)

Provided that such a combustion has a normal enthalpy,

ΔH°rxn = -1270 kJ/mol

That would be 1 mol reacting to release of ethanol,

⇒ -1270 kJ of heat

Now,

0.383 Ethanol mol responds to release or unlock,

(c) Determine the final temperature of the air in the room after the combustion.

Given that :

specific heat c = 1.005 J/(g. °C)

m = 5.56 ×10⁴ g

Using the relation:

q = mcΔT

- 486.34 =  5.56 ×10⁴  × 1.005 × ΔT

ΔT= (486.34 × 1000 )/5.56×10⁴  × 1.005

ΔT= 836.88 °C

ΔT= T₂ - T₁

T₂ =  ΔT +  T₁

T₂ = 836.88 °C + 21.7°C

T₂ = 858.58 °C

Therefore, the final temperature of the air in the room after combustion is 858.58 °C

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