Of the 32 students in Kimani's class, 8 students ride their bike to school, 5 walk to school, 4 get a ride to school in a car, a
nd 15 students take the bus to school.
Kimani created a spinner that represents the breakdown of how each student travels to class. He spun the spinner 20 times and recorded his results in the table
below.
How Students Get
to School
bike
walk
car
bus
Number of
Times
Bike 5
Walk 5
Car 2
Bus 8
What is the experimental probability that the spinner lands on the section labled "bus?
A. P(bus) = 1/10
B. P(bus) = 14
c. P(bus) = 1/8
D. P(bus) = 2/5
Kimani created a spinner that represents the breakdown of how each student travels to class. He spun the spinner 20 times and recorded his results in the table
below.
How Students Get
to School
bike
walk
car
bus
Number of
Times
Bike 5
Walk 5
Car 2
Bus 8
What is the experimental probability that the spinner lands on the section labled "bus?
A. P(bus) = 1/10
B. P(bus) = 14
c. P(bus) = 1/8
D. P(bus) = 2/5
1 answer:
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Answer:
The radius of the circle ,r= 1.43 m
The length of the side of square ,a= 2.77 m
Step-by-step explanation:
Given that
L= 20 m
Lets take radius of the circle =r m
The total parameter of the circle = 2π r
Area of circle ,A=π r²
The side of the square = a m
The total parameter of the square = 4 a
Area of square ,A'=a²
The total length ,L= 2π r+ 4 a
20 = 2π r+ 4 a
r=3.18 - 0.63 a
The total area = A+ A'
A" =π r² +a²
A"= 3.14(3.18 - 0.63 a)² + a²
For minimize the area
3.14 x 2(3.18 - 0.63 a) (-0.63) + 2 a = 0
3.14 x (3.18 - 0.63 a) (-0.63) + a = 0
-6.21 + 1.24 a + a=0
2.24 a = 6.21
a=2.77 m
r= 3.18 - 0.63 a
r= 3.18 - 0.63 x 2.77
r=1.43 m
Therefore the radius of the circle ,r= 1.43 m
The length of the side of square ,a= 2.77 m