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sertanlavr [38]
3 years ago
13

4) From a graphed linear line, how do you find the Slope: Y-intercept:

Mathematics
1 answer:
Ad libitum [116K]3 years ago
8 0

Rise over Run

Put the amount you go up or down on the Y-axis over how much you go right or the x-axis

the Y-intercept is found simply by looking where the graph crosses the y, if the equation is written instead of graphed, graph it using a graphing calculator, then use the information I gave you previously : )

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List 3 values that would make this inequality true for 7 + x < 13
Blizzard [7]
Three values that would make this true:

5
4
3
8 0
3 years ago
Helpppppppppppppppppppppppp
S_A_V [24]

Answer:

It is, D

Step-by-step explanation:

Your welcome for raising your test score

5 0
3 years ago
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How do u answer this I'm fratiomshow do you how do you do the San Francisco
Furkat [3]
No I do not know how to do this
5 0
3 years ago
Need help pls help me will mark first
Xelga [282]

Answer:

angles 5,6 are supplementary

angles 7 and 4 are vertical angles

(one solution of many)

Step-by-step explanation:

Lets start with supplementary angles. those are two angles that add up to 180 degrees or make a straight angle. Two angles that fulfill this statement are 5 and 6 because 5 and 6 make a straight angle.

Now lets do vertical angles. Vertical angles are angles that are opposite of each. They are made by intersecting diagonals. One pair of angles that fulfill this are angles 7 and 4. if you can tell, they are opposite of each other.

supplementary= 5 and 6

vertical= 7 and 4

have a wonderful day!

4 0
3 years ago
Read 2 more answers
Please help asap find f -1
ExtremeBDS [4]
I.
Given a function f with domain D and range R, and the inverse function 
f ^{-1},

then the domain of f ^{-1} is the range of f, and the range of f ^{-1} is the domain of f.

II. We are given the function f(x)= \sqrt{x-5},

the domain of f, is the set of all x for which \sqrt{x-5} makes sense, so x is any x for which x-5\geq0, that is x≥5.

the range is the set of all values that f can take. Since f is a radical function, it never produces negative values, in fact in can produce any value ≥0

Thus the Domain of f is [5, ∞) and the Range is [0, ∞)
then , the Domain of f ^{-1} is [0, ∞) and the Range of f ^{-1} is [5, ∞) 

III.
Consider f(x)= \sqrt{x-5}

to find the inverse function f^{-1}, 

1. write f(x) as y:

y= \sqrt{x-5}

2. write x in terms of y:

y= \sqrt{x-5}

take the square of both sides

y^{2} =x-5

add 5 to both sides

y^{2} +5=x

x=y^{2} +5

3. substitute y with x, and x with f^{-1}(x):

f^{-1}(x)=x^{2} +5


These steps can be applied any time we want to find the inverse function.

IV. Answer: 

f^{-1}(x)=x^{2} +5, x≥0

y≥0, where y are all the values that f^{-1} can take

Remark: the closest choice is B

8 0
3 years ago
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