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anzhelika [568]
3 years ago
11

PLEASE HELP ALMOST FINISHING ALBERA 1 PUT I NEED YOUR HELP PLEASE I BEG YOU BRAINLEST ANSWER!!!

Mathematics
2 answers:
Stels [109]3 years ago
8 0
44)
{(-2,1),(1,3),(3.2),(4,-2)}

45)
f(x)=7x+2
f(-1)=7(-1)+2=-7+2=-5
f(3)=7(3)+2=21+2=23
f(5)=7(5)+2=35+2=37
{5,23,37}

Select the table that represents the following graph
x      y
-1   -4
0     -1
1      2
2      5

Given f(x)=10x+4 and g(x)=3x-8
f(x)+f(x)=(10x+4)+(3x-8)=13x-4
13x-4

Question 49
f(x)=x²-3x and g(x)=4x⁵
f(x)*g(x)=(x²-3x)(4x⁵)=4x⁷-12x⁶
4x⁷-12x⁶

Question 50
(0,3)
f(x)=-2x/3 + 2
f⁻¹(x)=-3x/2+3
f⁻¹(0)=3

If the gradient of a hill is 8%...
2/25
2*(100%)/25=8%

Question 53
given two points (x₁,y₁) and (x₂,y₂)
m=slope
m=(y₂-y₁)/(x-x₁)
(2,5) and (1-4)
m=(-4-5) / (1-2)=-9/-1=9
9

Question 54
a decrease of 25 ant per minute
The following belows values...
K=y₁/x₁=-6/2=-3
-3

question 56
84 miles/4 gallons=189 miles/x
x=(189 miles * 4 gallons) / 84 miles=9 gallons
9 gallons

Question 57
4x+3y=1

Question 58
if x=0 ⇒ 4*0+5y=80  ⇒y=80/5=16
16


Dima020 [189]3 years ago
4 0

can you help me please

Determine if the relationship presented is an example of a direct variation or not. Explain your reasoning. The area, A, of a square whose side length is n. fellow algebra student!!

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How to do this plz tell​
VARVARA [1.3K]
3. = 6/12
6. = 4/6
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Hope this helps !
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3 years ago
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Aproximate value of <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%20%7B12" id="TexFormula1" title="\sqrt{x} {12" alt="\sqrt{x
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3 years ago
Which of the following nonlinear inequalities is graphed below
Rashid [163]

Answer:

(x²/4) + (y²/16) ≤ 1

Step-by-step explanation:

The general form of the ellipse in the graph is

x²/4 + y²/16 = 1

we want to find the inequality which represents the shaded area this will determine whether which of the following 2 choices are correct

Choice 1: x²/4 + y²/16 ≥ 1

Choice 2: x²/4 + y²/16 ≤ 1

we note that point (0,0) lies inside the shaded area. Which means if we substitute (0,0), it should create an equality that is valid.

try choice 1: 0²/4 + 0²/16  = 0 ≥ 1 (not valid because obviously zero is smaller than 1)  

try choice 1: 0²/4 + 0²/16  = 0 ≤ 1 (this is valid, hence choice 2  is the answer)

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3 years ago
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