What is the minimum volume of 5.50 M HCl necessary to neutralize completely the hydroxide in 718.0 mL of 0.183 M NaOH
1 answer:
The volume of HCl required is 23.89 mL
Calculation of volume:
The reaction:
As HCl and NaOH react in 1 : 1 ratio.
Volume of NaOH= 718 mL
Concentration= 0.183M
Volume of HCl= ?
Concentration= 5.50M
Using the dilution formula:
Therefore,
Volume of HCl required will be 23.89 mL.
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Sublimation is a process in which the solid molecules gain energy from their surrounding and they now have enough energy to overcome the force of attraction with the neighboring molecules, thus they escape into the surrounding without going through the liquid phase, that means they directly jump to the vapor phase.
<h2>_____________________________________</h2><h2>Endothermic</h2>Those process which absorb energy from their surrounding to form the product are called endothermic process. Since the SUBLIMATION requires additional energy, it is an endothermic change.
<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2><h2 />