48.3 g AgNO3 / 169.9 g/mol = 0.284 moles AgNO3
0.284 mol AgNO3 X (1 mol Ag2CrO4/2 mol AgNO3) = 0.142 mol Ag2CrO4
0.142 mol Ag2CrO4 X 331.7 g/mol = 47.1 g Ag2CrO4
<span>The term used by meteorologists for predicting the we ather is </span>forecasting
Answer:
Never smoke near a place where hydrogen is generated or being used. Remove all possible sources of flame and sparks. Hydrogen should only be generated and used in a well ventilated out door area. Precautions must be taken to remove all possibilities of fire or explosion.
The mass of a present which has a density of 2.15 kg/L and volume of 3650 mL is 7.74 kg.
<h3>How do we calculate mass?</h3>
Mass of any substance will be calculate by using the density and volume by using the below equation as:
Density = Mass / Volume
Given that,
Density of Christmas present = 2.15 kg/L
Volume of present = 3,650 mL = 3.6L
On putting values, we get
Mass = (2.15)(3.6) = 7.74
Hence required mass of Christmas present is 7.74 kg.
To know more about density, visit the below link:
brainly.com/question/10441359
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