The number of moles present in 29.5 grams of argon is 0.74 mole.
The atomic mass of argon is given as;
Ar = 39.95 g/mole
The number of moles present in 29.5 grams of argon is calculated as follows;
39.95 g ------------------------------- 1 mole
29.5 g ------------------------------ ?
Thus, the number of moles present in 29.5 grams of argon is 0.74 mole.
<em>"Your question seems to be missing the correct symbol for the element" </em>
Argon = Ar
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What are your answer choices? Scientists express the weight in AMU’s so that they can easily think about the weight of the atom. If it is expressed in grams, they’re constantly dealing with a weight that’s around 10^-24 grams, which is hard to deal with.
Answer:
Explanation:
The Ideal Gas Law states that PV=nRT.
Rearrange that into P/n=RT/V.
In this case, the cylinder is rigid so the volume, V, does not change.
Temperature does not change either.
Out of 450 grams of gas, 150 grams leak out. So only 450-150 = 300 grams is left.
n is number of moles which is dependent on mass:
n1/n2 = 450/300 = 3/2
P1/n1 = RT/V = P2/n2
P2 = P1/n1*n2
= 7.2/3*2
= 4.8 atmosphere
The appropriate answer is b. A metallic bond allows metals to conduct electricity. Metallic bonds are formed by atoms of metals in which the outer electrons of the atoms from a common electron cloud. In metallic bonding the atoms are not used up in the actual bond but are shared so they are free to move about to conduct electricity. Electrons in the other bond types are held in place in the molecule an are not free to move about so they cannot conduct electricity.
Answer:
NH^4NO^3
Explanation:
Ammonium nitrate, (NH4NO3), a salt of ammonia and nitric acid, used widely in fertilizers and explosives.
