If a chemical reaction catalyzed by an enzyme is being carried out, and there is a sudden, drastic decrease in temperature, the thing that will most likely to happen next is going to be the :
“enzyme activity will decrease, and the reaction will proceed very slowly, or possibly not at all.“
Explanation:
This compliance is required to how enzymes bind to other molecules and cause chemical reactions to occur on those molecules. Lowering the temperature reduces the motion of molecules and atoms, expecting this compliance is reduced or lost. As the temperature decreases, so do enzyme activity. While higher temperatures do increase the activity of enzymes and the rate of reactions,
The correct description that holds true for the above question would be B. Atomic number - 29 and Mass Number - 63.
Answer:
The answer to your question is Volume = 11.4 L
Explanation:
Data
Volume 1 = V1 = 6 L
Pressure 1 = P1 = 1 atm
Temperature 1 = T1 = 22°C
Volume 2 = V2 = ?
Pressure 2 = 0.45 atm
Temperature 2 = -21°C
Process
1.- Convert temperature (°C) to °K
T1 = 273 + 22 = 295°K
T2 = 273 + (-21) = 252°K
2.- Use the combined gas law to solve this problem
P1V1 / T1 = P2V2 / T2
-Solve for V2
V2 = P1V1T2 / T1P2
-Substitution
V2 = (6)(1)(252) / (295)(0.45)
- Simplification
V2 = 1512 / 132.75
- Result
V2 = 11.38 L
Given what we know, we can confirm that if further increases in substrate concentration do not result in further increases in reaction rate, then an enzyme is likely saturated.
<h3>What does it mean for an enzyme to be saturated?</h3>
Enzymes work by binding to the substrate in specific zones of the enzyme. The zones are known as the active sites on enzymes. Since enzymes have a limited amount of these zones, once they are all bonded to a substrate, we can say that it is saturated.
Therefore, the saturation of enzymes allows us to explain how further increases in substrate concentration do not result in further increases in reaction rate.
To learn more about enzymes visit:
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