Graph 2y is less than or equal to 5

Show that the statement is true. If GH has endpoints G(−2, 1) and H(4, −1), then the midpoint M of GH lies on the line y = −x +

Alex777 [14]

Midpoint = (x1 + x2) / 2, (y1 + y2)/2
(-2,1)....x1 = -2 and y1 = 1
(4,-1)...x2 = 4 and y2 = -1
time to sub
m = (-2 + 4) / 2 , (1 + (-1) / 2
m = (2/2), (0/2)
m = (1,0) <==

y = -x + 1.....(1,0)...x = 1 and y = 0
0 = -1 + 1
0 = 0 (correct)

so the midpoint M (1,0) lies on the line since its coordinates satisfy the equation <===

7 0

3 years ago

What number is: a composite, has 4 factors and some of it's multiples are 44 & 88?

Nadya [2.5K]

A delightful question.
I think I have it.

The number is 22 .

Its factors are 1, 2, 11, and 22 .

3 0

3 years ago

What is the total cost of a pair of jeans that are priced $40.00 if there is a 6.5% sales tax? $40.65 $42.60 $44.00 $46.50

-Dominant- [34]

A pair of jeans = $40.00
There is a 6.5% sales tax.

First change the % into a decimal by moving the decimal point two spaces to the left.
0.065

Multiply that by 40.00 to find out how much the tax is.

40 × 0.065 = 2.6

Now add the tax to the initial price.
40.00 + 2.6 = 42.60

The total cost is $42.60.

8 0

3 years ago

Read 2 more answers

Max travel 324 miles in six hours write the unit rate

Amiraneli [1.4K]

Answer:

54mph

Step-by-step explanation:

Answer:

= 54 miles per hour

Showing WorkThis is a fraction equal to

324 miles ÷ 6 hours

We want a unit rate where

1 is in the denominator,

so we divide top and bottom by 6

324 miles

÷ 6

6 hours

÷ 6

=

54 miles

1 hour

=

54 miles

hour

= 54 miles per hour

4 0

3 years ago

Read 2 more answers

All vectors are in Rn. Check the true statements below:

Oduvanchick [21]

Answer:

A), B) and D) are true

Step-by-step explanation:

A) We can prove it as follows:

$Proy_{cv}y=\frac{(y\cdot cv)}{||cv||^2}cv=\frac{c(y\cdot v)}{c^2||v||^2}cv=\frac{(y\cdot v)}{||v||^2}v=Proy_{v}y$

B) When you compute the product Ax, the i-th component is the matrix of the i-th column of A with x, denote this by Ai x. Then, we have that $||Ax||=\sqrt{(A_1 x)^2+\cdots (A_n x)^2}$ . Now, the colums of A are orthonormal so we have that (Ai x)^2=x_i^2. Then $||Ax||=\sqrt{(x_1)^2+\cdots (x_n)^2}=||x||$ .

C) Consider $S=\{(0,2),(2,0)\}\subseteq \mathbb{R}^2$ . This set is orthogonal because $(0,2)\cdot(2,0)=0(2)+2(0)=0$ , but S is not orthonormal because the norm of (0,2) is 2≠1.

D) Let A be an orthogonal matrix in $\mathbb{R}^n$ . Then the columns of A form an orthonormal set. We have that $A^{-1}=A^t$ . To see this, note than the component $b_{ij}$ of the product $A^t A$ is the dot product of the i-th row of $A^t$ and the jth row of $A$ . But the i-th row of $A^t$ is equal to the i-th column of $A$ . If i≠j, this product is equal to 0 (orthogonality) and if i=j this product is equal to 1 (the columns are unit vectors), then $A^t A=I$

E) Consider S={e_1,0}. S is orthogonal but is not linearly independent, because 0∈S.

In fact, every orthogonal set in R^n without zero vectors is linearly independent. Take a orthogonal set $\{u_1,u_2\cdots u_p\}$ and suppose that there are coefficients a_i such that $a_1u_1+a_2u_2\cdots a_nu_n=0$ . For any i, take the dot product with u_i in both sides of the equation. All product are zero except u_i·u_i=||u_i||. Then $a_i||u_i||=0$ then $a_i=0$ .

5 0

4 years ago