Answer:
The correct option is B.
Explanation:
Muscle tissues of the heart refers to a group of cells that are carrying out similar functions in the heart. There are three different types of muscles, these are skeletal, cardiac and smooth muscles. The cardiac muscles are found in the heart, they form the contractile wall of the heart. These muscle contract involuntarily ( that is, without any external stimulation) and they are single nucleus, striated and short.
9 possible outcomes.
1. There are two coins being flipped.
Possibilities:
HH (two heads) HT (heads and tails) TT (two tails)
There are three sides to the spinner
Possibilities:
Side 1 Side 2 Side 3
Since there are 3 possibilities for each, multiply them together
So, 3*3 which equals 9 possibilities
If a plant cell had a mutation such that the cyclic electron flow is observed at a much higher rate, which photosystem is most likely mutated such that energy is absorbed at a lower rate?
PSI
PSII
Answer:
PSII
Explanation:
Non-cyclic phosphorylation involves both PSI and PSII. The process starts with the splitting of water and excitation of electrons of the reaction center of PSII upon the absorption of solar energy at the wavelength of 680 nm. Any mutation in PSII would not allow the non-cyclic phosphorylation to occur when only cyclic phosphorylation would occur. The process of cyclic phosphorylation includes only PS I. Its reaction center absorbs maximum light at 700 nm and is cycled back while supporting ATP synthesis. Therefore, if a plant performs cyclic phosphorylation at a higher rate and absorbs less energy, this means that mutation was in PSII.
What you meant must be the adaptive advantage of the frogs' lungs. Frogs are considered as amphibians wherein the have this unique ability to reside either on land or in water. Their specialised lungs could be responsible to these which makes them capable of breathing oxygen in water and land.
Answer:
C. NAD⁺
Step-by-step explanation:
NADH is oxidized to NAD⁺ in Complex I of the Electron Transport Chain.
NADH ⟶ NAD⁺ + H⁺ + 2e⁻
The electrons continue through the Electron Transport Chain, and the NAD⁺ is used in three places during the Krebs Cycle.
(a) Isocitrate to oxalosuccinate
Isocitrate + NAD⁺ ⟶ oxalosuccinate + NADH + H⁺
(b) α-Ketoglutarate to succinyl-CoA
α-ketoglutarate + NAD+ + CoA → succinyl CoA + CO₂ + NADH
(c) Malate to oxaloacetate
Malate + NAD⁺ ⟶ oxaloacetate + NADH + H⁺
The NADH produced by these three reactions can then be used by Complex I in the Electron Transport Chain.
