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Fantom [35]
3 years ago
5

Solve the following system of equations. What is one x-value of a solution?

Mathematics
1 answer:
gulaghasi [49]3 years ago
5 0

Answer:

There is some mistake in the question, because the solutions are x = -1.445 and x = -34.555

Step-by-step explanation:

Given the functions:

f(x) = x² + 4x + 10

g(x) = -32x - 40

we want to find the points at which f(x) = g(x).

x² + 4x + 10 = -32x - 40

x² + 4x + 10 + 32x + 40 = 0

x² + 36x + 50 = 0

Using quadratic formula:

x = \frac{-b \pm \sqrt{b^2-4(a)(c)}}{2(a)}

x = \frac{-36 \pm \sqrt{36^2-4(1)(50)}}{2(1)}

x = \frac{-36 \pm 33.11}{2}

x_1 = \frac{-36 + 33.11}{2}

x_1 = -1.445

x_2 = \frac{-36 - 33.11}{2}

x_2 = -34.555

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