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Otrada [13]
3 years ago
9

Compressional forces within the crust can produce:

Physics
1 answer:
brilliants [131]3 years ago
4 0
<span>tension, compression, and shearing and can i get brainliest plz</span>
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Consider an object moving in the plane whose location at time t seconds is given by the parametric equations: x(t)=5cos(πt) y(t)
ololo11 [35]

Answer:

a)

a = 1/5

b = 1/3

b)

x(1/3) = 2.500

y(1/3) = 2.598

c)

x'(t) = -5π sin(π t)

d)

x'(1/3) = -13.603

Explanation:

Hi!

a)

We can notice that

x(t)/5 = cos(πt)

y(t)/3 = sin(πt)

Therefore:

( x(t) / 5 )^2 + ( y(t) / 3 )^2 = cos^2(πt) + sin^2(πt) = 1

That is:

a = 1/5

b = 1/3

b)

At t=1/3

x(1/3) = 5 cos(π/3)

y(1/3) = 3 sin(π/3)

But

cos(π/3) = 1/2 = 0.5

sin(π/3) = √3 / 2 = 0.866

That is:

x(1/3) = 2.5

y(1/3) = 2.598

c)

The horizontal velocity is:

x'(t) = -5π sin(π t)

d)

at time t =1/3

x'(1/3) = -5π sin(π/3) = -13.603

7 0
3 years ago
Will is a scientist. He’s designing a spacecraft that would allow people to land on Mars. Will’s mass on Earth is 75 kilograms.
Vesnalui [34]
Mass will remain unchanged, always.  His weight, which is the gravitational force acting on that mass will be less in this case.
6 0
3 years ago
Read 2 more answers
You are to drive to an interview in another town, at a distance of 310 km on an expressway. The interview is at 11:15 a.m. You p
Sloan [31]

Answer:

Explanation:

Time to cover first 100 km = 1 hour.

time remaining = 3.15 - 1 = 2.15 hour .

Time to cover next 42 km = 1 hour .

Time remaining = 2.15-1 = 1.15 hour.

Distance to be covered = 310 - 142

= 168 km

least speed needed = distance remaining / time remaining

= 168 / 1.15

= 146.08 km / h .

4 0
3 years ago
CAN AIR MAKE SHADOWS?
Tems11 [23]

Answer:

No because you cannot see air so therefore it cannot make shadows

Explanation:

3 0
3 years ago
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A certain electromagnetic wave traveling in seawater was observed to have an amplitude of 98.02 (V/m) at a depth of 10 m, and an
maksim [4K]

Answer:

The  value is   \alpha =  0.002 Np/m

Explanation:

From the question we are told that

  The first amplitude of the wave is  E_{max}1 =  98.02 \  V/m

  The first  depth  is  D_1 =  10 \  m

   The second amplitude is  E_{max}2 =  81.87 \  (V/m)

   The second depth is D_2 = 100 \ m

Generally from the spatial wave equation we have

   v(x) =  Ae^{-\alpha d}cos(\beta x  + \phi_o)

=>       \frac{v(x)}{v(x)} =\frac{  Ae^{-\alpha d}cos(\beta x  + \phi_o)}{ Ae^{-\alpha d}cos(\beta x  + \phi_o)}

So considering the ratio of the equation for the  two depth

\frac{A}{A_S}  =  \frac{e^{-D_1 \alpha }}{e^{-D_2 \alpha }}

=>   \frac{98.02}{81.87}  =  \frac{e^{-10 \alpha }}{e^{-100 \alpha }}

=>   \alpha  =  \frac{0.18}{90}

=>    \alpha =  0.002 Np/m

       

4 0
3 years ago
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