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damaskus [11]
3 years ago
11

A skydiver is jumping from an airplane traveling at 10.0 m/s. The plane is 3520 m above the earth. The sky diver pulls his cord

at 1760 m above the earth. Neglecting air resistance, how far does the skydiver travel horizontally before pulling the cord?
x=____
a.3590m
b.134m
c.190m
Physics
2 answers:
ikadub [295]3 years ago
6 0
Given:
<span>velocity = 10.0 m/s.
The plane is 3520 m above the earth. The sky diver pulls his cord at 1760 m above the earth.</span>
gravity = 9.8 m/s²

Δheight = initial height - final height = gt²/2 

time =√(2 • Δh/g) 
time =√{2 • (3520-1760)/9.8}
time =√{2 * 179.59 s²
time = √359.18
time = 18.95 s. 

s=vt=10•18.95=189.5m or 190m

<span>The skydiver traveled 190m horizontally before pulling the cord.</span>

wlad13 [49]3 years ago
5 0

Answer:

c.190m horizontally

Explanation:

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