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damaskus [11]
3 years ago
11

A skydiver is jumping from an airplane traveling at 10.0 m/s. The plane is 3520 m above the earth. The sky diver pulls his cord

at 1760 m above the earth. Neglecting air resistance, how far does the skydiver travel horizontally before pulling the cord?
x=____
a.3590m
b.134m
c.190m
Physics
2 answers:
ikadub [295]3 years ago
6 0
Given:
<span>velocity = 10.0 m/s.
The plane is 3520 m above the earth. The sky diver pulls his cord at 1760 m above the earth.</span>
gravity = 9.8 m/s²

Δheight = initial height - final height = gt²/2 

time =√(2 • Δh/g) 
time =√{2 • (3520-1760)/9.8}
time =√{2 * 179.59 s²
time = √359.18
time = 18.95 s. 

s=vt=10•18.95=189.5m or 190m

<span>The skydiver traveled 190m horizontally before pulling the cord.</span>

wlad13 [49]3 years ago
5 0

Answer:

c.190m horizontally

Explanation:

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3 years ago
On Venus, the acceleration due to gravity is 8.87 m / s 2 . How far would a 17 g rock fall from rest in 6.5 s if the only force
algol [13]

Answer:

187.38 m

Explanation:

Using the equation of motion

s = ut + 1/2gt²...................... Equation 1

Where s = distance of fall, u = initial velocity of the rock, t = time taken for the rock to fall from rest, g = acceleration due to gravity of venus.

Given: u = 0 m/s ( from rest), t = 6.5 s, g = 8.87 m/s².

substituting into equation 1

s = 0(6.5) + 1/2(8.87)(6.5)²

s = 0 + 374.7575/2

s = 187.38 m.

Hence the rock will fall 187.38 m

7 0
3 years ago
Please help! the mass of an object is measured on a pan balance with a precision of 0.005 g and the recorded value of 128.01 g.
inysia [295]

Yes, these two objects have different masses.

<h3>How can we calculate that this statement is right ?</h3>

To calculate the precision of mass we are using the formula,

Precision(P) = \frac{m_1}{m_1+\triangle m}

Or,\trianglem=\frac{m_1}{P}-m₁

For the first case we are given,

m₁= The recorded value of mass

= 128.01 g

P= Precision of the mass

=0.005g

So, according to the formula, \trianglem will be,

\trianglem=  \frac{128.01}{0.005}-128.01

Or,\trianglem=25,473.99 g

Or,\trianglem=25.47 Kg

For the first case \trianglem is 25.47 Kg..

For the second case we are given,

m₁= The recorded value of mass

= 0.13 Kg

P= Precision of the mass

=0.005 Kg

So, according to the formula, \trianglem will be,

\trianglem= \frac{0.13}{0.005}-0.13

Or,\trianglem= 25.87 kg

For the second case \trianglem is 25.87 Kg.

For the two cases  \trianglem has different values, 25.47 Kg≠25.87 Kg.

Therefore we can conclude that, these two objects have different masses.

Learn more about Mass:

brainly.com/question/3187640

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