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neonofarm [45]
3 years ago
6

Will is a scientist. He’s designing a spacecraft that would allow people to land on Mars. Will’s mass on Earth is 75 kilograms.

Will knows that the gravitational pull of Mars is less than the gravitational pull of Earth. When he lands on Mars, his mass will be (Less than, Equal to or More than) 75 kilograms. His weight on Mars will be (less than, Equal to, or more than) his weight on Earth.
Physics
2 answers:
s2008m [1.1K]3 years ago
8 0

Mass is the amount of substance present inside the body.

As per Einstein's relativity the mass of the body increases with the increase of the speed of the body.

Mathematically it is given as m=\frac{m_{0} }{\sqrt{1-\frac{v^2}{c^2} } }

where m is the mass of the body during motion and m_{0} is the rest mass.

Here V is the velocity of the body and c is the speed of light.

But during non-relativistic situation i.e the velocity of the body is very very less as compared to the velocity of the light or equal to zero, the mass of the substance remains unchanged.

Hence mass of Will will be the same both in Mars and Earth i.e 75 kg

Again the weight of a body is mathematically given as -

                             weight= mass×acceleration due to gravity

                           i.e W= m×g

The value of g is less in Mars as compared to Earth.

Hence the weight of Will on Mars is less as compared to weight on the Earth.

Vesnalui [34]3 years ago
6 0
Mass will remain unchanged, always.  His weight, which is the gravitational force acting on that mass will be less in this case.
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Are light waves longitudinal or transverse
Marysya12 [62]

Answer:

Transverse

Explanation:

There are two types of waves, according to the direction of their oscillation:

- Transverse waves: in a transverse wave, the direction of the oscillation is perpendicular to the direction of motion of the wave. Examples of transverse waves are electromagnetic waves

- Longitudinal waves: in a longitudinal wave, the direction of the oscillation is parallel to the direction of motion of the wave. Examples of longitudinal waves are sound waves.

Light waves corresponds to the visible part of the electromagnetic spectrum, which includes all the different types of electromagnetic waves (which consist of oscillations of electric and magnetic fields that are perpendicular to the direction of propagation of the wave): therefore, they are transverse waves.

6 0
3 years ago
: A 70 kg man and a 12 kg sled are on the frictionless ice of a frozen lake, 25 m apart but connected by a rope of negligible ma
e-lub [12.9K]

Answer:

x_1 = 3.74m

Explanation:

given,

mass of man = 70 kg

mass of sled = 12 kg

F = m a_s

a_s = \dfrac{F}{m}

a_s = \dfrac{8.2}{12}

a_s = 0.68\ m/s^2

F = m a_m

a_m = \dfrac{F}{m}

a_m = \dfrac{8.2}{70}

a_m = 0.12\ m/s^2

x_1+x_2 = 25

\dfrac{1}{2}a_ct^2+ \dfrac{1}{2}a_mt^2 = 25

(a_c+a_m)t^2=50

(0.12+0.68)t^2=50

t = \sqrt{\dfrac{50}{0.8}}

t = 7.90 s

x_1 = \dfrac{1}{2}a_ct^2

x_1 = 0.5\times 0.12 \times 7.90^2

x_1 = 3.74m

5 0
3 years ago
Which nucleus completes the following equation?
natka813 [3]
the answer is C




IGNORW irritating but not even on the golden bath bath and
3 0
3 years ago
A body of mass 25kg, moving at 3 ms per second on a rough horizontal floor brought to rest after sliding through a distance of 2
erastova [34]
You have to solve this by using the equations of motion:
u=3
v=0
s=2.5
a=?
v^2=u^2+2as
0=9+5s
Giving a=-1.8m/s^2

Then using the equation:
F=ma
F is the frictional force as there is no other force acting and its negative as its in the opposite direction to the direction of motion.

-F=25(-1.8)
F=45N

Then use the formula:
F=uR
Where u is the coefficient of friction, R is the normal force and F is the frictional force.

45=u(25g)
45=u(25*10)

Therefore, the coefficient of friction is 0.18

Hope that helps




5 0
3 years ago
Dierdre drew a diagram to compare the three types of mirrors.
Sholpan [36]

<em>Labels that belong in the marked ares X, Y & Z include;</em>

X: Curves outward

Y: Image may be smaller than object

Z: Image is always virtual

<u>Since the rays never meet, the images formed by convex mirrors are always virtual and smaller than the object, and since they are smaller, the images appear to be further than they actually are.</u>

8 0
3 years ago
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