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neonofarm [45]
3 years ago
6

Will is a scientist. He’s designing a spacecraft that would allow people to land on Mars. Will’s mass on Earth is 75 kilograms.

Will knows that the gravitational pull of Mars is less than the gravitational pull of Earth. When he lands on Mars, his mass will be (Less than, Equal to or More than) 75 kilograms. His weight on Mars will be (less than, Equal to, or more than) his weight on Earth.
Physics
2 answers:
s2008m [1.1K]3 years ago
8 0

Mass is the amount of substance present inside the body.

As per Einstein's relativity the mass of the body increases with the increase of the speed of the body.

Mathematically it is given as m=\frac{m_{0} }{\sqrt{1-\frac{v^2}{c^2} } }

where m is the mass of the body during motion and m_{0} is the rest mass.

Here V is the velocity of the body and c is the speed of light.

But during non-relativistic situation i.e the velocity of the body is very very less as compared to the velocity of the light or equal to zero, the mass of the substance remains unchanged.

Hence mass of Will will be the same both in Mars and Earth i.e 75 kg

Again the weight of a body is mathematically given as -

                             weight= mass×acceleration due to gravity

                           i.e W= m×g

The value of g is less in Mars as compared to Earth.

Hence the weight of Will on Mars is less as compared to weight on the Earth.

Vesnalui [34]3 years ago
6 0
Mass will remain unchanged, always.  His weight, which is the gravitational force acting on that mass will be less in this case.
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katrin2010 [14]

Answer:

a) 0.036 J b) 0.036J c) 0.036 d) 1.9m/s e) 0.18 m

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Mass of the dart = 0.02kg, the spring was compressed to 6cm

Work needed to compress the spring = 1/2*k*x ^2 where k is the force constant of the spring in N/m, x is the distance it was compressed in m

Work needed to compress the spring = 0.5 * 20* 0.06^2 since 6cm = 6 / 100 = 0.06 m

Work needed to compress the spring = 0.036J

b) the total energy stored in the spring = the work done to compress the spring = 0.036J

c) kinetic energy of the dart as it leaves the the spring = elastic potential energy stored in the spring = the work done in compressing the = 0.036J using the law of conservation of energy; energy is neither created nor destroyed but transformed from one form to another.

d) 1/2mv^2 = 0.036

mv^2 = 0.036*2

v^2 = 0.036*2 / 0.02 = 3.6

v = √3.6 = 1.897 approx 1.9m/s

e) kinetic energy of the dart = work done against gravity to get the body to height h

Work done against gravity = potential energy conserved at height = -mgh g is negative because the motion is upward while gravity acts downward

0.036 = 0.02 * 9.81 * h

0.036 / ( 0.02*9.81) = h

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4 years ago
A force of 10N makes an angle of 30 degree with y-axis. The magnitude of X component will be?
andreev551 [17]
The magnitude of x component is 5N
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A 5.0 A electric current passes through an aluminum wire of 4.0~\times~10^{-6}~m^2 cross-sectional area. Aluminum has one free e
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n = \frac{\rho \times N_{A}}{M}\\= \frac{2.7 g/cm^{3} \times 6.02 \times 10^{23}/mol}{27 g/mol}\\= \frac{16.254 \times 10^{23}}{27} cm^{3}\\= 0.602 \times 10^{23} \times \frac{10^{6} cm^{3}}{1 m^{3}}\\= 6.0 \times 10^{28} m^{-3}

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Nutka1998 [239]
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