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daser333 [38]
3 years ago
8

Convert mass to moles for both reactants. 2.50g CuCl2 0.50g Al

Chemistry
1 answer:
alexandr402 [8]3 years ago
6 0

Answer:

Number of moles of Al = 0.02 mol

Number of moles of CuCl₂ = 0.02 mol

Explanation:

Given data:

Mass of CuCl₂ = 2.50 g

Moles of CuCl₂ = ?

Solution:

Formula:

Number of moles = mass / molar mass

Molar mass of CuCl₂  =  63.546 + 35.5 ×2

Molar mass of CuCl₂  =  134.546 g/mol

Now we will put the values in formula:

Number of moles = 2.50 g / 134.546 g/mol

Number of moles = 0.02 mol

Given data:

Mass of Al = 0.50 g

Moles of Al = ?

Solution:

Formula:

Number of moles = mass / molar mass

Molar mass of Al  =  27 g/mol

Now we will put the values in formula:

Number of moles = 0.50 g / 27 g/mol

Number of moles = 0.02 mol

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Mariulka [41]
The formula used for determining gas pressure, volume and temperature interaction would be PV=nRT. 

<span>• What is the temperature in Kelvins?
</span>You already right at this part. Kelvin temperature formula from celsius should be:
K= C+273.15= 
<span>K= 27 +273.15 = 300.15 
It is important to remember that the formula in this question is using Kelvin unit at temperature, not Celcius or Fahrenheit.
</span>
<span>• Assuming that everything else remains constant, what will happen to the pressure if the temperature decreases to -15 ºC?
</span>In this case, the temperature is decreased from 27C into -15C and you asked the change in the pressure.
Using PV=nRT formula, you can derive that the temperature will be directly related to pressure. If the temperature decreased, the pressure will be decreased too. 

<span> If you increase the number of moles to 6 moles, increase temperature to 400K and reduce the volume to 25 L, what will the new pressure be?
</span>PV=nRT
P= nRT/V
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3 0
2 years ago
Consider the following Reaction.
jeyben [28]

Hey there!:

Molar mass of Mg(OH)2 = 58.33 g/mol


number of moles Mg(OH)2 :

moles of Mg(OH)2 = 30.6 / 58.33 =>  0.5246 moles

Molar mass of H3PO4 =  97.99 g/mol

number of moles H3PO4:

moles of Mg(OH)2 = 63.6 / 97.99 => 0.649 moles

Balanced chemical equation is:


3 Mg(OH)2 + 2 H3PO4 --->  Mg3(PO4)2 + 6 H2O


3 mol of Mg(OH)2 reacts with 2 mol of H3PO4  ,for 0.5246 moles of Mg(OH)2, 0.3498 moles of H3PO4 is required , but we have 0.649 moles of H3PO4, so, Mg(OH)2 is limiting reagent !

Now , we will use Mg(OH)2 in further calculation  .

Molar mass of Mg3(PO4)2 = 262.87 g/mol

According to balanced equation  :

mol of Mg3(PO4)2 formed = (1/3)* moles of Mg(OH)2


= (1/3)*0.5246


= 0.1749 moles of Mg3(PO4)2

use :

mass of Mg3(PO4)2 = number of mol * molar mass


= 0.1749 *  262.87

= 46 g of Mg3(PO4)2

Therefore:

% yield = actual mass * 100 / theoretical mass

% = 34.7 * 100 / 46

% = 3470 / 46

= 75.5%


Hope that helps!




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Answer:

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Explanation:

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