Answer:
b 1 mole of nitrogen 6 hydro 1 sulfur
Fat: 1 gram = 9 calories Protein: 1 gram = 4 calories Carbohydrates: 1 gram = 4 calories Alcohol: 1 gram = 7 calories"
So, (12 g carbohydrates)*4 Cal=48 Cal; (9 g fat) *9 Cal=81 Cal; (9 g protein)*4 Cal=36 Cal
48 Cal + 81 Cal + 36 Cal = 165 Cal in one glass of milk
Answer:
There are 5 significant digits in 0.23100.
Explanation:
This is because all non-zero digits are considered significant and zeros after decimal points are considered significant.
Answer:
-138.9 kJ/mol
Explanation:
Step 1: Convert 235.8°C to the Kelvin scale
We will use the following expression.
K = °C + 273.15 = 235.8°C + 273.15 = 509.0 K
Step 2: Calculate the standard enthalpy of reaction (ΔH°)
We will use the following expression.
ΔG° = ΔH° - T.ΔS°
ΔH° = ΔG° / T.ΔS°
ΔH° = (-936.92kJ/mol) / 509.0K × 0.51379 kJ/mol.K
ΔH° = -3.583 kJ (for 1 mole of balanced reaction)
Step 3: Convert -9.9°C to the Kelvin scale
K = °C + 273.15 = -9.9°C + 273.15 = 263.3 K
Step 4: Calculate ΔG° at 263.3 K
ΔG° = ΔH° - T.ΔS°
ΔG° = -3.583 kJ/mol - 263.3 K × 0.51379 kJ/mol.K
ΔG° = -138.9 kJ/mol
Answer:
3.612 × 10^24 molecules
Explanation:
The balanced chemical equation in this question is given as;
2Al + 6HCl → 2AlCl3 + 3H2
Based on the equation, 2 moles of Aluminum (Al) is needed to react with 6 moles of HCl
Since 1 mole of a substance is equal to 6.02 × 10^23 molecules;
This means that, according to the question, 6 moles of HCl needed to react with 2 moles of Al will contain;
6 × 6.02 × 10^23 molecules
= 36.12 × 10^23
= 3.612 × 10^24 molecules
In a nutshell, 3.612 × 10^24 molecules of HCl would react with 2 moles of Al.
