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irina1246 [14]
3 years ago
12

3.05 moles of H2O is equivalent to (blank amount) molecules of water. Show your work.

Chemistry
1 answer:
ANTONII [103]3 years ago
6 0

Answer:

1 \: mole \:  = 6.02 \times  {10}^{23}  \: molecules \\ 3.05 \: moles \:  = (3.05 \times 6.02 \times  {10}^{23} ) \: molecules \\  = 1.8361 \times  {10}^{24}  \: molecules

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grigory [225]

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1. 2,3,2

2. 4,5,2

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7 0
2 years ago
Molecular and empirical formulas
shepuryov [24]

Answer:

See below

Explanation:

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7 0
2 years ago
The amount of gas that occupies 36.52 L at 68.0°C and 672 mm Hg is __________ mol.
ASHA 777 [7]
We assume that this gas is an ideal gas. We use the ideal gas equation to calculate the amount of the gas in moles. It is expressed as:

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Hope this answers the question. Have a nice day.
7 0
2 years ago
Help me plz #10 would appreciate it
DaniilM [7]
C I’m pretty sure. I can explain just lmk
7 0
3 years ago
In the reaction, A → Products, the rate constant is 3.6 × 10−4 s−1. If the initial concentration of A is 0.548 M, what will be t
Arada [10]

Answer:

        \large\boxed{\large\boxed{0.529M}}

Explanation:

Since the <em>rate constant</em> has units of <em>s⁻¹</em>, you can tell that the order of the reaction is 1.

Hence, the rate law is:

       r=d[A]/dt=-k[A]

Solving that differential equation yields to the well known equation for the rates of a first order chemical reaction:

      [A]=[A]_0e^{-kt}

You know [A]₀, k, and t, thus you can calculate [A].

       [A]=0.548M\times e^{-3.6\cdot 10^{-4}/s\times99.2s}

       [A]=0.529M

7 0
3 years ago
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