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Dmitry [639]
3 years ago
12

Given that you have 14.5 moles of n2, how many moles of h2 are theoretically needed to produce 30.0 moles of nh3 according to re

action below?

Chemistry
2 answers:
erastovalidia [21]3 years ago
7 0

45 moles of H₂ are theoretically needed to produce 30.0 moles of NH₃

<h3>Further explanation</h3>

Stoichiometry in Chemistry learn about chemicals mainly emphasizes quantitative, such as the calculation of volume, mass, number, which is related to numbers, molecules, elements, etc.

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

In the reaction there are also manifestations of reagent substances namely gas (g), liquid (liquid / l), solid (solid / s) and solution (aqueous / aq).

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

  • Mole

The mole itself is the number of particles contained in a substance amounting to 6.02.10²³

Mole can also be sought if the amount of substance mass and its molar mass is known

\large{\boxed{\boxed{\bold{mol=\frac{mass}{molar\:mass}}}}

 

Reaction that happens :

N₂ +3H₂ ⇒ 2NH₃

mole N₂ : H₂ : NH₃ = 1 : 3 : 2

To produce 30.0 moles of NH₃,

  • H₂ needed :

mole~H_2~=~\frac{3}{2}\times~30~mole

mole H₂ = 45 mole

  • N₂ needed :

mole~N_2~=~\frac{1}{2}~\times~30

mole N₂ = 15 mole

So the minimum N₂ needed is: 15 mole

14.5 moles of N₂ can only produce NH₃ :

mole~NH_3~=~\frac{2}{1}~\times~14.5

mole NH₃ = 29 mole

<h3>Learn more </h3>

The mass of one mole of raindrops

brainly.com/question/5233234

moles of NaOH

brainly.com/question/4283309

moles of water you can produce

brainly.com/question/1405182

 

Keywords: mole,  NH₃, N₂, H₂

frutty [35]3 years ago
4 0

\boxed{45 \text{mol}} of \text{H}_2 are theoretically needed to produce 30.0 moles of  .

Further Explanation:

Stoichiometry is used to describe quantitative relationship between reactants and products. In stoichiometric problems, amount of one of the species involved in the reaction can be calculated with the help of known amounts of other species in the same reaction.

Consider a reaction of the general form as follows:

\text{X}+2\text{Y}\rightarrow3\text{Z}

Where,

X and Y are reactants of reaction.

Z is the product of reaction.

The stoichiometry of this reaction indicates that one mole of X can react with two moles of Y and three moles of Z are produced.

The balanced chemical reaction for the formation of   is as follows:

\text{N}_2+3\text{H}_2\rightarrow2\text{NH}_3

According to balanced chemical reaction, one mole of \text{N}_2 reacts with three moles of  \text{H}_2 to form two moles of  \text{NH}_3. So stoichiometric ratio between  \text{H}_2 and \text{NH}_3  is 3:2.

Since three moles of hydrogen produce two moles of \text{NH}_3, moles of \text{H}_2 that are required to form 30.0 moles of \text{NH}_3 can be calculated as follows:

\begin{aligned}\text{Moles of H}_2=&\left ({\dfrac{\text{3 Mol of H}_2}{\text{2 Mol of NH}_3} \right )\left(30\text{mol of NH}_3\right)\\=& 45.0\text{ mol of H}_2\end{aligned}

Hence 45.0 moles of \text{H}_2 are required to produce 30.0 moles of \text{NH}_3 .

Learn more:

  1. How many moles of Cl are present in 8 moles of  ? brainly.com/question/3064603
  2. Calculate the moles of ions in HCl solution: brainly.com/question/5950133

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Mole concept

Keywords: NH3, 45 mol, H2, N2, stoichiometry, balanced chemical reaction, one mole, two moles, three moles, X, Y, Z, 2Y, 3Z, 3H2, 2NH3, quantitative relationship.

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Question 7 of 15
Crazy boy [7]

Answer: 0.4 moles

Explanation:

Given that:

Volume of gas V = 11L

(since 1 liter = 1dm3

11L = 11dm3)

Temperature T = 25°C

Convert Celsius to Kelvin

(25°C + 273 = 298K)

Pressure P = 0.868 atm

Number of moles N = ?

Note that Molar gas constant R is a constant with a value of 0.00821 atm dm3 K-1 mol-1

Then, apply ideal gas equation

pV = nRT

0.868atm x 11dm3 = n x (0.00821 atm dm3 K-1 mol-1 x 298K)

9.548 atm dm3 = n x 24.47atm dm3mol-1

n = (9.548 atm dm3 / 24.47atm dm3 mol-1)

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Thus, there are 0.4 moles of the gas.

3 0
3 years ago
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Answer:

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Explanation:

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7 0
3 years ago
How many grams of KBr is required to prepare 100 mL of<br> 2.0 M KBr solution?
sesenic [268]

Answer:

23.8g

Explanation :

Convert 2.0M into mol using mol= concentration x volume

2.0M x 0.1L (convert 100mL to L since the units for M is mol/L)

= 0.2 mol

We can now find grams by using the molar mass of KBr

=119.023 g/mol (Found online) webqc.org

but can be be calculated by using the molecular weight of K and Br found on the periodic table

We can now calculate the grams by using grams=mol x molar mass

119.023g/mol x 0.2mol

= 23.8046 g

=23.8g (rounded to 1decimal place)

4 0
3 years ago
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