Answer:
The probability that a family spends less than $410 per month
P( X < 410) = 0.1151
Step-by-step explanation:
<u><em>Step(i):-</em></u>
<em>Given mean of the population = 500 </em>
<em>Given standard deviation of the Population = 75</em>
Let 'X' be the variable in normal distribution
<em>Given X = $410</em>
<em></em><em></em>
<u><em>Step(ii):-</em></u>
The probability that a family spends less than $410 per month
P( X < 410) = P( Z < - 1.2 )
= 0.5 - A( -1.2)
= 0.5 - A(1.2)
= 0.5 - 0.3849 ( ∵from normal table)
= 0.1151
<u>Final answer:-</u>
The probability that a family spends less than $410 per month
P( X < 410) = 0.1151
Looks like the system is
We can eliminate by taking
so that , and
Substitute into this last equation and solve for :
Then
Plug these values into any one of the original equation to solve for :
Hence the solution is x = 4, y = -3, and z = 2.
The answer to this question is true. Based on my knowledge and research, the deviation is, in fact, the difference between any value and the mean of the entire set.
Step-by-step explanation:
20÷4=20/4=5 is the quotient I'm pretty sure