4 years ago

Please help A-22 B-24 C-28 D-34

Mathematics

1 answer:

QveST [7]4 years ago

6 0

The answer is 22 babe

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Answer:

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Step-by-step explanation:

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3 years ago

Simplify the radical expression.. square root of 128

Vaselesa [24]

Hello,

first we have to descompose the number:

128 | 2
64 | 2
32 | 2
16 | 2
8 | 2
4 | 2
2 | 2
1

So:
$128= 2x2x2x2x2x2x2 \\ 128=2^{6} *2$

Therefore:
$\sqrt{128}= \sqrt{2^{6} *2}$

You must know these properties:

$\sqrt{a*b} = \sqrt{a} * \sqrt{b}\\ \\ \sqrt[b]{x^a}= x^{ \frac{a}{b}}$

then:

$\sqrt{2^{6} *2} \\ =\sqrt{2^{6}}*\sqrt{2} \\ =2^{ \frac{6}{2}}*\sqrt{2} \\ =2^3*\sqrt{2} \\ \boxed{=8*\sqrt{2}}$

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4 years ago