The deepest point known in any of the earth's oceans is in the marianas trench, 10.92 km deep. assuming water to be incompressib

Question

Naddika [18.5K]

4 years ago

9

The deepest point known in any of the earth's oceans is in the marianas trench, 10.92 km deep. assuming water to be incompressib

le, what is the pressure at this depth? (use density of seawater 1027 kg/m3).]\

Physics

2 answers:

Drupady [299] · Answer 1 · 2022-02-06T08:10:34+03:00

The pressure at the depth of the Marianas trench is $\boxed{1.10\times{{10}^8}\,{\text{Pa}}}$ .

Further Explanation:

Given:

The depth of the Marianas Trench is $10.92\,{\text{km}}$ .

The density of the sea water is $1027\,{{{\text{kg}}}\mathord{\left/{\vphantom{{{\text{kg}}}{{{\text{m}}^{\text{3}}}}}}\right.\kern-\nulldelimiterspace}{{{\text{m}}^{\text{3}}}}}$ .

Concept:

The pressure due to a liquid varies due to the variation in the depth $d$ of the point from the surface. The variation of the pressure is given by:

$P=\rho gh$

Here, $P$ is the pressure at the depth, $\rho$ is the density of the sea water, $g$ is the acceleration due to gravity and $h$ is the depth from the surface.

Substitute the values of the density, acceleration die to gravity and the depth of the point from the surface in the above expression:

$\begin{aligned}P&=1027\times9.81\times\left({10.92\times{{10}^3}}\right)\,{\text{Pa}}\\&=1007.48\times10.92\times{10^3}\,{\text{Pa}}\\&=1.10\times{10^8}\,{\text{Pa}}\\\end{aligned}$