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3 years ago

A dog of mass 18 kg runs at a speed of 4 m/s. What is the momentum of the

Physics

1 answer:

Andrej [43]3 years ago

6 0

Answer:

A, 72 kg•m/s

Explanation:

p=mv

p=18x4

p=72

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A transmission diffraction grating with 420 lines/mm is used to study the light intensity of di event orders (n). A screen is lo

Goshia [24]

Answer:

Explanation:

Diffraction grating is used to form interference pattern of dark and bright band.

Distance between adjacent slits (a ) = 1 / 420 mm

= 2.38 x 10⁻³ mm

2.38 x 10⁻⁶ m

wave length of red light

= 680 x 10⁻⁹ m

For bright red band

position x on the screen

= n λD / a , n = 0,1,2,3 etc

D = distance of screen

putting n = 1 , 2 and 3 , we can get three locations of bright red band.

x₁ = λD / a

= 680 x 10⁻⁹ x 2.8 / 2.38 x 10⁻⁶

= .8 m

= 80 cm

Position of second bright band

= 2 λD / a

= 2 x 80

= 160 cm

Position of third bright band

= 3 λD / a

= 3 x 80

= 240 cm

5 0

3 years ago

Which object has the most gravitational potential energy?

Kipish [7]

Answer: An 8 kg book at a height of 3 m has the most gravitational potential energy.

Explanation:

Gravitational potential energy is the product of mass of object, height of object and gravitational field.

So, formula to calculate gravitational potential energy is as follows.

U = mgh

where,

m = mass of object

g = gravitational field = $9.81 m/s^{2}$

h = height of object

(A) m = 5 kg and h = 2m

Therefore, its gravitational potential energy is calculated as follows.

$U = mgh\\= 5 kg \times 9.81 m/s^{2} \times 2 m\\= 98.1 J (1 J = kg m^{2}/s^{2})$

(B) m = 8 kg and h = 2 m

Therefore, its gravitational potential energy is calculated as follows.

$U = mgh\\= 8 kg \times 9.81 m/s^{2} \times 2 m\\= 156.96 J (1 J = kg m^{2}/s^{2})$

(C) m = 8 kg and h = 3 m

Therefore, its gravitational potential energy is calculated as follows.

$U = mgh\\= 8 kg \times 9.81 m/s^{2} \times 3 m\\= 235.44 J (1 J = kg m^{2}/s^{2})$

(D) m = 5 kg and h = 3 m

Therefore, its gravitational potential energy is calculated as follows.

$U = mgh\\= 5 kg \times 9.81 m/s^{2} \times 3 m\\= 147.15 J (1 J = kg m^{2}/s^{2})$

Thus, we can conclude that an 8 kg book at a height of 3 m has the most gravitational potential energy.

3 0

3 years ago

Maria designs a test to see if lemon trees that receive more water produce larger lemons.

denis-greek [22]

Do you know the answer

7 0

3 years ago

Which of these would have the lowest albedo?

kati45 [8]

All black surfaces is the correct answer

3 0

2 years ago

During the launch from a board, a diver's angular speed about her center of mass changes from zero to 8.10 rad/s in 240 ms. Her

Artemon [7]

Answer:

Part a)

$\alpha = 33.75 rad/s^2$

Part b)

$\tau = 391.5 Nm$

Explanation:

Part a)

Average angular acceleration is given as rate of change in angular speed

so it is given as

$\alpha = \frac{\omega_f - \omega_i}{\Delta t}$

$\alpha = \frac{8.10 - 0}{240\times 10^{-3}}$

$\alpha = 33.75 rad/s^2$

Part b)

average external torque is given as

$\tau = I\alpha$

here we know that

$I = 11.6 kg m^2$

$\tau = 11.6 \times 33.75$

$\tau = 391.5 Nm$

6 0

3 years ago