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const2013 [10]
2 years ago
10

Determine the launch speed of a horizontally launched projectile that lands 26.3m from the base of a 19.3m high cliff

Physics
1 answer:
mote1985 [20]2 years ago
5 0

The launch speed of a horizontally launched projectile is 13.28 m/s.

<h3>Time of motion of the projectile</h3>

The time of motion is calculated as follows;

t = √(2h / g)

where;

  • h is height of the cliff
  • g is acceleration due to gravity

t = √(2 x 19.3 / 9.8)

t = 1.98 s

<h3>Launch speed of the projectile</h3>

X = Vxt

Vx = X/t

Vx = (26.3)/(1.98)

Vx = 13.28 m/s

Thus, the launch speed of a horizontally launched projectile is 13.28 m/s.

Learn more about horizontal speed here: brainly.com/question/24949996

#SPJ1

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const2013 [10]

The velocity of the cannonball is 150 m/s,  the right option is B. 150 m/s.

The question can be solved, using Newton's second law of motion.

Note: Momentum of the cannon = momentum of the cannonball.

<h3>Formula:</h3>
  • MV = mv................. Equation 1

<h3>Where:</h3>
  • M = mass of the cannon
  • m = mass of the cannonball
  • V = velocity of the cannon
  • v = velocity of the cannonball

Make v the subject of the equation.

  • v = MV/m................ Equation 2

From the question,

<h3>Given: </h3>
  • M = 500 kg
  • V = 3 m/s
  • m = 10 kg.

Substitute these values into equation 2.

  • v = (500×3)/10
  • v = 150 m/s.

 

Hence, The velocity of the cannonball is 150 m/s,  the right option is B. 150 m/s.

Learn more about Newton's second law here: brainly.com/question/25545050

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