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weeeeeb [17]
3 years ago
7

Match the following associations. Exothermic or endothermic

Chemistry
1 answer:
Alekssandra [29.7K]3 years ago
8 0

<u>Answer:</u>

<em>1) ∆H is positive \Rightarrow Endothermic </em>

<em>2) E_p>E_r \Rightarrow Endothermic  </em>

<em>3) Energy is absorbed \Rightarrow Endothermic </em>

<em>4) E_r>E_p \Rightarrow Exothermic </em>

<em>5) ∆H is negtive \Rightarrow Exothermic </em>

<em></em>

<u>Explanation:</u>

∆H is called as enthalpy change  

It is also called as Heat of reaction

Energy is required for the bond to break a bond.

Energy is released when a bond is formed.

H_2+Cl_2>2HCl

that is

H-H+Cl-Cl>2H-Cl

We see in this equation, bonds between hydrogen and chlorine molecules gets broken and on the right side bond is formed in HCl.

If energy of products greater than energy of reactants then the reaction enthalpy change is endothermic .

If energy of products lesser than energy of reactants then the reaction enthalpy change is exothermic .

For example  

\Delta H=E_p-E_r

=30KJ-20KJ

=+10KJ

(positive hence endothermic)

\Delta H=E_p-E_r

=10KJ-40KJ

=-30KJ

(negative hence exothermic)

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Oxygen is composed of three isotopes: oxygen-16, oxygen-17 and oxygen-18 and has an average atomic mass of 15.9982 amu. Oxygen-1
Irina-Kira [14]

Answer:

The percent abundance of oxygen-18 is 1.9066%.

Explanation:

The average atomic mass of oxygen is given by:

m_{O} = m_{^{16}O}*\%_{16} + m_{^{17}O}*\%_{17} + m_{^{18}O}*\%_{18}

Where:

m: is the atomic mass

%: is the percent abundance

Since the sum of the percent abundance of oxygen isotopes must be equal to 1, we have:  

1 = \%_{16} + \%_{17} + \%_{18}

1 = x + 3.2 \cdot 10^{-4} + \%_{18}

\%_{18} = 1 - x - 3.2 \cdot 10^{-4}

Hence, the percent abundance of O-18 is:  

m_{O} = m_{^{16}O}*\%_{16} + m_{^{17}O}*\%_{17} + m_{^{18}O}*\%_{18}  

15.9982 = 15.972*x + 16.988*3.2 \cdot 10^{-4} + 17.970*(1 - 3.2 \cdot 10^{-4} - x)

x = 0.980614 \times 100 = 98.0614 \%                                                              

Hence, the percent abundance of oxygen-18 is:

\%_{18} = (1 - 3.2 \cdot 10^{-4} - 0.980614) \times 100 = 1.9066 \%                      

Therefore, the percent abundance of oxygen-18 is 1.9066%.

I hope it helps you!                                                      

8 0
2 years ago
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<u>Answer:</u> The number of molecules of carbon dioxide gas are 2.815\times 10^{21}

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{CO_2}=K_H\times p_{CO_2}

where,

K_H = Henry's constant = 0.034mol/L.atm

C_{CO_2} = molar solubility of carbon dioxide gas

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Putting values in above equation, we get:

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Putting values in above equation, we get:

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Hence, the number of molecules of carbon dioxide gas are 2.815\times 10^{21}

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