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Nesterboy [21]
3 years ago
10

What are the uses of polythene ?

Chemistry
1 answer:
fomenos3 years ago
3 0

Polyethylene or Polythene is one of the most common plastics used all around the world. It is very widely produced, with around 80 million tonnes every single year!

It is used for the following

  • Plastic bags
  • Plastic films
  • Geomembranes (low permeable sheets that act like a barrier or a line separating two substances to control fluids)
  • Dustbin crates
  • Water pipes
  • Plastic bottles
  • Packaging

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Are these mixtures or pure substance?
Archy [21]
A mixture is a system that is made up of two or more substances which are not combined chemically. A pure substance is a system that only has one substance. The following are classified as:
1.water : pure substance
<span>2.blood : mixture</span>
<span>3.the oceans : mixture</span>
<span>4.iron : pure substance
5.brass : mixture</span>
<span>6.uranium : pure substance</span>
<span>7.wine : mixture</span>
<span>8.leather : mixture</span>
<span>9.table salt (NaCl) : pure substance</span>
4 0
2 years ago
Calculate the wavelength, in nanometers, of the light emitted by a hydrogen atom when its electron fallsfrom the n = 7 to the n
Helga [31]

Answer:

λ=2167.6 nm

The wavelength of light emitted is 2167.6 nm.

Explanation:

We recall that Eₙ=\frac{-2.18*10^{-18} J}{n^{2} }

since there was transition from n7 to n=4 we will first calculate the change in the energy i.e ΔE

ΔE=E₄-E₇

ΔE=-2.18*10^{-18} J(\frac{1}{4^{2} } -\frac{1}{7^{2} } )

ΔE=-9.1760*10^-20 J

Now:

|ΔE|=Energy of photon=h*v=h*c/λ

λ=h*c/|ΔE|

λ=\frac{6.63*10^{-34}J.s*3.00*10^{8}m/s  }{9.1760*10^{-20} J }

λ=2.1676*10^-6 m

λ=2167.6*10^-9 m

λ=2167.6 nm

The wavelength of light emitted is 2167.6 nm.

5 0
3 years ago
Shoe companies imbed unique designs on the bottoms of the sneakers they manufacture. What is the main purpose of the designs on
Andreas93 [3]
It is to increase friction
3 0
3 years ago
The Lyman series results from excited state hydrogen atoms transiting to
Nutka1998 [239]

Answer:

I can't draw diagrams on this web site but I can do with numbers I think. So an electron is moved from n = 1 to n = 5. I'm assuming I've interpreted the problem correctly; if not you will need to make a correction. I'm assuming that you know the electron in the n = 1 state is the ground state so the 4th exited state moves it to the n = 5 level.

n = 5 4th excited state

n = 4 3rd excited state

n = 3 2nd excited state

n = 2 1st excited state

n = 1 ground state

Here are the possible spectral lines.

n = 5 to 4, n = 5 to 3, n = 5 to 2, n = 5 to 1 or 4 lines.

n = 4 to 3, 4 to 2, 4 to 1 = 3 lines

n = 3 to 2, 3 to 1 = 2 lines

n = 2 to 1 = 1 line. Add 'em up. I get 10.

b. The Lyman series is from whatever to n = 1. Count the above that end in n = 1.

c.The E for any level is -21.8E-19 Joules/n^2

To find the E for any transition (delta E) take E for upper n and subtract from the E for the lower n and that gives you delta E for the transition.

So for n = 5 to n = 1, use -Efor 5 -(-Efor 1) = + something which I'll leave for you. You could convert that to wavelength in meters with delta E = hc/wavelength. You might want to try it for the Balmer series (n ending in n = 2). I think the red line is about 650 nm.

Explanation:

8 0
2 years ago
ILL GIVE BRAINLIST............ have to answer all!!!!
7nadin3 [17]
1 is seconds and meters m/s

2 is seconds and meters m/s^2

3 Newton kg/m

4 Kilograms

Hope this helps!
6 0
3 years ago
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