You are given the neutralization of acetic acid with sodium hydroxide. Also, you are given the k for acetic acid, which is 1.8 x 10⁻⁵. You are asked to find the<span> approximate value of the equilibrium constant, kn, for the neutralization. We will have a reaction of both acetic acid and sodium hydroxide.
CH</span>₃COOH + NaOH → CH₃COONa + H₂O
which comes from
CH₃COOH → CH₃COO⁻ + H⁺
H⁺ + OH⁻ → H₂O<span>
</span>The k for water is always 1.0 x 10¹⁴. The Ksp for the reaction will be
<span>
Ksp = [</span>CH₃COOH][H₂O]
Ksp = (1.8 x 10⁻⁵)(1.0 x 10¹⁴)
<span>Ksp = 1.8 x 10</span>⁹
Because each color is refracted differently, each bends at a different angle, resulting in a fanning out and separation of white light into the colors of the spectrum. Water droplets in the air can act in a manner similar to that of a prism, separating the colors of sunlight to produce a spectrum known as a rainbow.
Answer 1 : The balanced complete ionic equation will be,
By removing the spectator ion in this equation, we get the balanced ionic equation.
Answer 2 : The balanced net ionic equation will be,
By removing the spectator ion in this equation, we get the balanced ionic equation.
Answer 3 : The balanced net ionic equation will be,
By removing the spectator ion in this equation, we get the balanced ionic equation.
Balanced equations : Balanced equations are the equations in which the number of individual elements present on the reactant side must be equal to the number of individual elements present on the product side.
Spectator ions : It is defined as the ions which do not participate in the chemical reaction. These ions exists in the same form on both the sides of the reaction.
B it is an aldose to ketose isomerization
The concentration of [Sn⁺²] will be calculated by first calculating the moles of SnCl₂ added as these moles will give us the moles of [Sn⁺²] ion.
Moles of SnCl₂ = molarity X volume = 0.04 X 2.60 = 0.104 milli moles [as volume is in mL]
The moles of [Sn⁺² = 0.104 mmol
the total volume in solution = volume due to MO + volume due to SnCl₂ + volume due to HCl + volume due to NaCl
Total volume = 8+2.60+5.43+3.73= 19.76 mL
Concentration = moles / volume
concentration [Sn⁺²] = 0.104mmol / 19.76 mL = 0.0053 mol / L
