Question

When the hydraulic conductivity Ks = 10 mm/hr; effective matrix potential Ns = 20 mm, and rainfall intensity I = 30 mm/hr , determine the amount of runoff generated when the runoff rate reaches 15 mm/hr?( 2.7 mm or 0.21 mm or 18 mm or 0.67 mm)

Answer 1

Answer:

$t = 0.75 \ hr = 0.75 *60 = 45 \ minutes$

Explanation:

From the question we are told that

   The  hydraulic conductivity is  $Ks = 10\ mm/hr$

    The  effective matrix potential $Ns = 20 \ mm$

    The  intensity of  rainfall is  $I = 30 \ mm/hr$

    The runoff rate $R = 15 \ mm/hr$

Generally the run off rate is mathematically represented as  

      $R = (I - Ks) t$

Here t is the amount of runoff generated

=>   $15 = (30 - 10) t$

=>  $t = 0.75 \ hr$

converting to minutes

    $t = 0.75 \ hr = 0.75 *60 = 45 \ minutes$