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Answer:
The coefficient of friction and acceleration are 0.37 and 2.2 m/s²
Explanation:
Suppose we find the coefficient of friction and the acceleration of the 100 kg block during the time that the 60 kg block remains in contact.
Given that,
Mass of block = 60 kg
Acceleration = 2.0 m/s²
Mass = 100 kg
Horizontal force = 340 N
Let the frictional force be f.
We need to calculate the frictional force
Using balance equation

Put the value into the formula



We need to calculate the coefficient of friction
Using formula of friction force




We need to calculate the acceleration of the 100 kg block
Using formula of newton's law




Hence, The coefficient of friction and acceleration are 0.37 and 2.2 m/s²
Density is defines as the ratio of mass to volume.
So you measure the mass and volume of a sample, and
divide the mass by the volume, to find the density.
Answer:
W = 112.58 N-unit
Explanation:
Given:
- Force F = 10 N
- Angle Q of force with x axis: 30 degrees
- distance to be moved d = 13 units along + x axis
Find:
Work Done by the force F:
Solution:
The work by force in positive x direction can only be done if the both the direction of distance traveled and direction of force are parallel vectors. Hence we compute the component of Force F in x direction F_x:
F_x = F*cos(Q)
F_x = 10*cos(30)
F_x = 8.66 N
Hence,
Work Done by force
W = F_x * d
W = 8.66 * 13
W = 112.58 N-unit