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Alja [10]
3 years ago
7

mastering biology ch 3 Water molecules have a polarity, which allows them to be electrically attracted to other water molecules

and other polar molecules by weak chemical bonds known as

Chemistry
1 answer:
aniked [119]3 years ago
7 0

Answer:

The answer to your question is: hydrogen bonding

Explanation:

Hydrogen bonding is a kind of interaction dipole-dipole, that means that 2 molecules attract each other because the have partial charges.

In the picture we can see 4 molecules of water, red circles are oxygens and white circles are hydrogens. In this bonding, Oxygen due to its size, and atomic number is more electronegative than hydrogen, then in water molecule is formed a partial negative charge in oxygen and a partial positive charge in hydrogen.

Finally, because of this partial charge, one oxygen can bond to one hydrogen of another molecule.

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Solve this word problem:
valina [46]

Answer:

The new acceleration becomes twice the pervious acceleration.

Explanation:

Given that,

Mass of the rock, m = 3 kg

Force, F = 1 N

We know that the force acting on an object is given by :

F = ma

a is acceleration of the rock

Put m = 3 kg and F = 1N,

a=\dfrac{F}{m}\\\\a=\dfrac{1}{3}\ m/s^2

If the force is doubled, F' = 2 N

So,

F'=ma'

a'=\dfrac{F'}{m}\\\\a'=\dfrac{2\times 1}{3}\\\\a'=\dfrac{2}{3}\\\\a'=2\times \dfrac{1}{3}\\\\a'=2a

So, the new acceleration becomes twice the initial acceleration.

3 0
3 years ago
Temperature of the water to the nearest degree:___ °C
forsale [732]

Answer:

From the image the answer is 24.

8 0
3 years ago
Read 2 more answers
Draw the Lewis structure for NF3. What orbitals on N and F overlap to form bonds between these elements
jonny [76]
Is there a picture ????????????
4 0
2 years ago
Group the following electron configurations in pairs that would represent similar chemical properties at their atoms;
marishachu [46]

<u>Answer:</u> Pairs are:  (a) and (d), (b) and (f), (c) and (e)

<u>Explanation:</u>

In a periodic table, elements are arranged in 18 vertical columns known as groups and 7 horizontal rows known as periods.

Elements arranged in a group show similar chemical properties because of the presence of same number of valence electrons.

Valence electrons are defined as the electrons which are present in the outermost shell of an atom. Outermost shell has the highest value of 'n' that is principal quantum number.

For the given options:

  • <u>For a:</u>

The given electronic configuration is:  1s^22s^22p^63s^2

The number of valence electrons in the given configuration are 2

  • <u>For b:</u>

The given electronic configuration is:  1s^22s^22p^63s^3

The number of valence electrons in the given configuration are [2 + 3] = 5

  • <u>For c:</u>

The given electronic configuration is:  1s^22s^22p^63s^23p^64s^23d^{10}4p^6

The number of valence electrons in the given configuration are [2 + 6] = 8

  • <u>For d:</u>

The given electronic configuration is:  1s^22s^2

The number of valence electrons in the given configuration are 2

  • <u>For e:</u>

The given electronic configuration is:  1s^22s^22p^6

The number of valence electrons in the given configuration are [2 + 6] = 8

  • <u>For f:</u>

The given electronic configuration is:  1s^22s^22p^63s^23p^3

The number of valence electrons in the given configuration are [2 + 3] = 5

Electronic configuration of (a) and (d) will form a pair, (b) and (f) will form a pair, (c) and (e) will form a pair and will have similar chemical properties.

Hence, the pairs are:  (a) and (d), (b) and (f), (c) and (e)

4 0
3 years ago
2Mg + O2 → 2MgO<br><br> If you are burning 5.8332 g of Mg, how many grams of MgO will this make?
LekaFEV [45]
<h3>Answer:</h3>

9.6724 g MgO

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Stoichiometry</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2Mg + O₂ → 2MgO

[Given] 5.8332 g Mg

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol Mg = 2 mol MgO

Molar Mass of Mg - 24.31 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of MgO - 24.31 + 16.00 = 40.31 g/mol

<u>Step 3: Stoichiometry</u>

  1. Set up:                              \displaystyle 5.8332 \ g \ Mg(\frac{1 \ mol \ Mg}{24.31 \ g \ Mg})(\frac{2 \ mol \ MgO}{2 \ mol \ Mg})(\frac{40.31 \ g \ MgO}{1 \ mol \ MgO})
  2. Multiply/Divide:                                                                                               \displaystyle 9.67241 \ g \ MgO

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 5 sig figs.</em>

9.67241 g MgO ≈ 9.6724 g MgO

5 0
3 years ago
Read 2 more answers
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