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3 years ago

What is the oxidation number of an element?

Chemistry

1 answer:

tatiyna3 years ago

7 0

Answer:

Oxidation number is the total number of electrons that an atom either gains or loses in order to form a chemical bond with another atom.

Hope this helps

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How are radio waves transmitted

kotegsom [21]

Attractive antennas that pull the waves tword it.

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3 years ago

Boyle's law states that the pressure of a gas is always:

natka813 [3]

Answer:

d. inversely proportional to the volume of its container.

Explanation:

Boyle's law states that at constant temperature and number of moles, the pressure of the gas is inversely proportional to the volume of the gas.

Thus, P ∝ T

P is the pressure

T is the temperature

For two gases at same temperature, the law can be written as:-

${P_1}\times {V_1}={P_2}\times {V_2}$

<u>Thus, according to the question, the answer is:- d. inversely proportional to the volume of its container.</u>

7 0

3 years ago

In chemistry, what varies with the number of molecules present in a sample of a particular substance?

Neko [114]

Answer: concentration

Explanation:

Concentration refers to the amount of a substance present in a sample. The more molecules of a substance present in a sample, the greater its concentration. The less molecules of a substance in a sample, the lesser the concentration. We are often concerned about analytically determining the concentration of a substance using diverse analytical methods in chemistry.

3 0

3 years ago

A magnet sticks to an iron can and an iron rod. This is an intrinsic property. <br> True or false?

lesantik [10]

Answer:

True

Explanation:

Well,I hope it helps....

Just correct me if I'm wrong..

8 0

3 years ago

The equilibrium constant for the reaction is 1.1 x 106 M. HONO(aq) + CN-(aq) ⇋ HCN(aq) + ONO-(aq) This value indicates that

kakasveta [241]

The given question is incomplete. The complete question is given here :

The equilibrium constant for the reaction is $1.1\times 10^6$ M.

$HONO(aq)+CN^- (aq)\rightleftharpoons HCN(aq)+ONO^-(aq)$

This value indicates that

A. $CN^-$ is a stronger base than $ONO^-$

B. HCN is a stronger acid than HONO

C. The conjugate base of HONO is $ONO^-$

D. The conjugate acid of CN- is HCN

Answer: A. $CN^-$ is a stronger base than $ONO^-$

Explanation:

Equilibrium constant is the ratio of product of the concentration of products to the product of concentration of reactants.

When $K_{p}>1$ ; the reaction is product favoured.

When $K_{p};$ ; the reaction is reactant favored.

$When K_{p}=1$ ; the reaction is in equilibrium.

As, $K_p>>1$ , the reaction will be product favoured and as it is a acid base reaction where $HONO$ acts as acid by donating $H^+$ ions and $CN^-$ acts as base by accepting $H^+$

Thus $HONO$ is a strong acid thus $ONO^-$ will be a weak conjugate base and $CN^-$ is a strong base which has weak $HCN$ conjugate acid.

Thus the high value of K indicates that $CN^-$ is a stronger base than $ONO^-$

7 0

3 years ago