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3 years ago

How was Bohr’s atomic model different from Rutherford’s atomic model?

2 answers:

7 0

• Rutherford model suggested a new look into the nature of the nucleus, whereas the Bohr model suggested a new look into the mechanics of electrons.

• Bohr model utilized the existing knowledge of the nucleus derived from the Rutherford model.

• Rutherford model is based on the experiments Rutherford conducted in collaboration with Geiger and Marsden. The Bohr model is based on existing experimental results.

anzhelika [568]3 years ago

3 0

Answer:

Bohr’s model showed that electron orbits had distinct radii.

Explanation:

Bohr’s atomic model stated that electrons move in definite orbits. Electron shells are quantized. Electrons could move in the 1st, 2nd, 3rd shell etc. As electrons move in definite orbits they are at distinct distance from the nucleus. Thus each orbit has a distinct and different radii from the nucleus of the atom.

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What is the smallest particle of a covalent compound that has the properties of that compound?

Shtirlitz [24]

The smallest particle is the white blood cells because they are the ones that help you breathe

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3 years ago

What is true of all eukaryotic organisms?

Basile [38]

Answer:

They are multicelled

Explanation:

I just did a quiz on it UwU

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3 years ago

Which of the following represents six molecules of water? 6HO 2 6H 2O 1 6H 2O H 6O

n200080 [17]

Answer:

6H20 represents six molecules of water

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3 years ago

Read 2 more answers

7. The equilibrium constant Kc for the reaction H2(g) + I2(g) ⇌ 2 HI(g) is 54.3 at 430°C. At the start of the reaction there are

Juli2301 [7.4K]

Answer:

[H2] = 0.0692 M

[I2] = 0.182 M

[HI] = 0.826 M

Explanation:

Step 1: Data given

Kc = 54.3 at 430 °C

Number of moles hydrogen = 0.714 moles

Number of moles iodine = 0.984 moles

Number of moles HI = 0.886 moles

Volume = 2.40 L

Step 2: The balanced equation

H2 + I2 → 2HI

Step 3: Calculate Q

If we know Q, we know in what direction the reaction will go

Q = [HI]² / [I2][H2]

Q= [n(HI) / V]² /[n(H2)/V][n(I2)/V]

Q =(n(HI)²) /(nH2 *nI2)

Q = 0.886²/(0.714*0.984)

Q =1.117

Q<Kc This means the reaction goes to the right (side of products)

Step 2: Calculate moles at equilibrium

For 1 mol H2 we need 1 mol I2 to produce 2 moles of HI

Moles H2 = 0.714 - X

Moles I2 = 0.984 -X

Moles HI = 0.886 + 2X

Step 3: Define Kc

Kc = [HI]² / [I2][H2]

Kc = [n(HI) / V]² /[n(H2)/V][n(I2)/V]

Kc =(n(HI)²) /(nH2 *nI2)

KC = 54.3 = (0.886+2X)² /((0.714 - X)*(0.984 -X))

X = 0.548

Step 4: Calculate concentrations at the equilibrium

[H2] = (0.714-0.548) / 2.40 = 0.0692 M

[I2] = (0.984 - 0.548) / 2.40 = 0.182 M

[HI] = (0.886+2*0.548) /2.40 = 0.826 M

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3 years ago

Read 2 more answers

One compound that contributes to the "seashore smell" at beaches in Hawaii is dictyopterene D', a component of a brown edible se

Luba_88 [7]

Answer:

Explanation:

There are few simple rules in organic chemistry which a person must learn.

1. In predicting a structure from ozonolysis, number of oxygen present in products must be counted. In this particular example, there are 2+3+1 = 6 oxygen atoms are present in three molecules. This means that there should be at least three confirmed double bonds must be present in the molecule of Dictyopterene.

2. There are in total of 3+5+3 = 11 carbon atoms present, making 2^11 = 2048 possible structures for this particular structure. But since there are three double bonds present, this will reduce the number of possible structures as well.

3. Questions also says that when fully hydrogenated, the molecule generates Butylcycloheptane. That means that our base molecule is Butylcycloheptane and this molecule contains at least three double bonds.

So, first we draw the molecule of butylcycloheptane. After this, we think of were double bonds could be present. We do have the products. Let's make their structures first. I have also mentioned the possible breakup where the ozonolysis has occured by color code. You can see them in the reference image attached.

Part 1 out of 2: There is only one chiral carbon present in the molecule and have two possible isomers. Cis and Trans. Only one stereogenic carbon is present, that's why two possible isomers. Image attached.

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3 years ago