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jeyben [28]
3 years ago
8

How was Bohr’s atomic model different from Rutherford’s atomic model?

Chemistry
2 answers:
kherson [118]3 years ago
7 0

• Rutherford model suggested a new look into the nature of the nucleus, whereas the Bohr model suggested a new look into the mechanics of electrons.

• Bohr model utilized the existing knowledge of the nucleus derived from the Rutherford model.

• Rutherford model is based on the experiments Rutherford conducted in collaboration with Geiger and Marsden. The Bohr model is based on existing experimental results.


anzhelika [568]3 years ago
3 0

Answer:

C.  

Bohr’s model showed that electron orbits had distinct radii.

Explanation:

Bohr’s atomic model stated that electrons move in definite orbits. Electron shells are quantized. Electrons could move in the 1st, 2nd, 3rd shell etc. As electrons move in definite orbits they are at distinct distance from the nucleus. Thus each orbit has a distinct and different radii from the nucleus of the atom.

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Explanation:

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Therefore, reaction equation when an aluminum- nuclide transforms into a phosphorus- nuclide by absorbing an alpha particle and emitting a neutron is as follows.

        ^{27}_{13}Al + ^{1}_{0}n \rightarrow ^{30}_{15}P + ^{1}_{0}n

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Which letter corresponds with the location of f orbitals on the periodic table?
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Explanation:

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8 0
2 years ago
For the following reaction, 4.07 grams of aluminum oxide are mixed with excess sulfuric acid. The reaction yields 10.4 grams of
torisob [31]

Answer:

Theoretical yield = 13.7 g

% yield =76 %

Explanation:

For Al_2O_3

Mass of Al_2O_3  = 4.07 g

Molar mass of Al_2O_3  = 101.96 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{4.07\ g}{101.96\ g/mol}

Moles\ of\ Al_2O_3= 0.0399\ mol

According to the reaction:

Al_2O_3+3H_2SO_4\rightarrow Al_2(SO_4)_3+3H_2O

1 mole of Al_2O_3  on reaction produces 1 mole of Al_2(SO_4)_3

So,  

0.0399 mole of Al_2O_3  on reaction produces 0.0399 mole of Al_2(SO_4)_3

Moles of Al_2(SO_4)_3  obtained = 0.0399 mole

Molar mass of Al_2(SO_4)_3 = 342.2 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

0.0399= \frac{Mass}{342.2\ g/mol}

Mass= 13.7\ g

<u>Theoretical yield = 13.7 g</u>

The expression for the calculation of the percentage yield for a chemical reaction is shown below as:-

\%\ yield =\frac {Experimental\ yield}{Theoretical\ yield}\times 100

Given , Values from the question:-

Theoretical yield = 13.7 g

Experimental yield = 10.4 g

Applying the values in the above expression as:-

\%\ yield =\frac{10.4}{13.7}\times 100

<u>% yield =76 %</u>

6 0
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Sloan [31]

Answer:

C

Explanation:

Bacteria lacks a nucleus.

4 0
2 years ago
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