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GrogVix [38]
4 years ago
13

Ice slurry is being transported in a pipe (k = 15 W/m∙K, Di = 0.025 m, Do = 0.08 m, and L = 5 m) with an inner surface temperatu

re of 0°C. The ambient condition surrounding the pipe has a temperature of 20°C, a convection heat transfer coefficient of 10 W/m2∙K, and a dew point of 10°C. If the outer surface temperature of the pipe drops below the dew point, condensation can occur on the surface. Since this pipe is located in the vicinity of high voltage devices, water droplets from the condensation can cause electrical hazard. To prevent such incident, the pipe surface needs to be insulated. Determine the insulation thickness for the pipe using a material with k = 0.95 W/m∙K to prevent the outer surface temperature from dropping below the dew point.
Engineering
1 answer:
grandymaker [24]4 years ago
3 0

Answer:

Please see the attached file for complete answer.

Explanation:

Download pdf
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Four race cars are traveling on a 2.5-mile tri-oval track. The four cars are traveling at constant speeds of 195 mi/h, 190 mi/h,
Snezhnost [94]

Answer:

Explanation:

1) The number of times, the car with the speed of  195 mph will cross the given point is equal to 30 minutes divided by the time taken by car to cross the 2.5 miles.

0 .5*195/2.5 = 39

Likewise, the car with the speed of 190 mph crosses the point 38 times; the car with the speed of 185 mph crosses the point 37 times

and car with the speed of 180 mph crosses it 36 times

here, the time-mean speed, vt is given below,

vt = (39*195 +38*190+37*185+36*180)/(39+38+37+38)

= 186.433 mph

and space mean speed is given by,

= (39+38+37+36)/(39/195+38/190+37/1850+36/180)

1) The number of times, the car with the speed of  195 mph will cross the given point is equal to 30 minutes divided by the time taken by car to cross the 2.5 miles.

0 .5*195/2.5 = 39

Likewise, the car with the speed of 190 mph crosses the point 38 times; the car with the speed of 185 mph crosses the point 37 times

and car with the speed of 180 mph crosses it 36 times

here, the time-mean speed, vt is given below,

vt = (39*195 +38*190+37*185+36*180)/(39+38+37+38)

= 186.433 mph

and space mean speed is given by,

= (39+38+37+36)/(39/195+38/190+37/1850+36/180)

=187.5 mph

2)  There would be only four number of observations when the aerial photo is given, therefore time mean speed, vt in that condition will be calculated as

Vt = 195+190+185+180/4

  = 187.5

Vs= 4/(1/195+1/190+1/185+1/180)

= 188.36 mph

2)  There would be only four number of observations when the aerial photo is given, therefore time mean speed, vt, in that condition will be calculated as

Vt = 195+190+185+180/4

  = 187.5

Vs= 4/(1/195+1/190+1/185+1/180)

= 188.36 mph

4 0
4 years ago
How did ancient machines pave the way for improvement
Leno4ka [110]

Answer:

----------

Explanation:

Ancient machines have paved the way for improvement by being the foundation for change. these machines made it possible to find flaws so in the next generations, they could fix, develop, and produce better quality machines. eventually this process has reached the present time but after today, the process will continue to produce even better quality machines than the time before. I hope this helps!

4 0
3 years ago
In an air compressor the compression takes place at a constant internal energy and 50KJ of heat are rejected to the cooling wate
lozanna [386]

Answer:

work is 50 kj

Explanation:

Given  data

heat (Q) = 50 kj

To find out

work input for the compression stroke per kilogram of air

Solution

we will apply here "first law of thermodynamics" i.e.

The First Law of Thermodynamics states that heat is a form of energy, subject to the principle of conservation of energy, that heat energy cannot be created or destroyed. It can be transferred from one location to another  location. i.e.

ΔU = Q – W                        ................1

here ΔU is change in internal energy, Q is heat and W is work done

here U = 0 because air compressor the compression takes place at a constant internal energy in question

so that by equation 1

Q = W

and Q = 50

so work will be 50 kj

8 0
3 years ago
A master precision square is used to validate the
kumpel [21]

Answer:

me you same I didn't understand good luck

4 0
2 years ago
A bearing is to be used as shaft support to carry both radial and thrust forces. Calculations show that a 02 series ball bearing
shepuryov [24]

Answer:

The correct answer is "20.8 kN" and "31 kN". A further explanation is given below.

Explanation:

  • The angular touch bearing seems to be a fine replacement while accommodating radial and even some displacement pressures.
  • You may receive static as well as dynamic scores from either the manufacturer's collections.  

The load ratings should be for the SKF bearing including its predetermined distance:

Static load

= 20.8 kN

Dynamic load

= 31 kN

4 0
3 years ago
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