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3 years ago

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The minimum recommended standards for the operating system, processor, primary memory (RAM), and storage capacity for certain so

ftware are called distribution standards. O vendor standards. O system requirements O hardware specifications.

2 answers:

nlexa [21]3 years ago

8 0

Answer:System requirements

Explanation:

its right.

ipn [44]3 years ago

8 0

Answer:

Explanation':

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6.8.1: Function pass by pointer: Transforming coordinates. Define a function CoordTransform() that transforms its first two inpu

Black_prince [1.1K]

Answer:

The code is in the Explanation

Explanation:

#include <iostream>

using namespace std;

int main() {

int xValNew = 0;

int yValNew = 0;

CoordTransform(3, 4, xValNew, yValNew);

cout << "(3, 4) becomes " << "(" << xValNew << ", " << yValNew << ")" << endl;

return 0;}

6 0

3 years ago

The water level in a tank z1, is 20 m above the ground. A hose is connected to the bottom of the tank, and the nozzle at the end

Alika [10]

Answer:

the maximum height h to which the the water steam could rise is 40.65m

Explanation:

Given;

$Z_{1}$ = 20m,

$P_{1gage}$ = 2atm ≈ 20265 N/m

Density of water ρ = 1000 kg/ $m^{2}$

Note: we take point 1 at the free surface of the water in the tank and point 2 at the top of the water trajectory. we also take reference level at the bottom of the tank.

fluid velocity at the free surface of tank is very low ( $V_{1}$ ≅ 0) and at the top of the water trajectory $V_{2}$ = 0

Step 1: Applying Bernoulli equation between poin 1 and point 2

$P_{1}$ /ρg + $V_{1} ^{2}$ /2g + $Z_{1}$ = $P_{2}$ /ρg + $V_{2} ^{2}$ /2g + $Z_{2}$

$P_{1}$ /ρg + $Z_{1}$ = $P_{atm}$ /ρg + $Z_{2}$

$Z_{2}$ = ( $P_{1}$ - $P_{atm}$ )/ρg + $Z_{1}$

Substituting values into $Z_{2}$ we have,

$Z_{2}$ = $\frac{2atm}{(1000 kg/m^{3} )(9.81 m/s^{2} )} (\frac{101325N/m^{2} }{1atm} )(\frac{1 kg.m/s^{2} }{1N} ) + 20 = 40.65 m$

6 0

3 years ago

Water flows in a pipeline. At a point in the line where the diameter is 7 in., the velocity is 12 fps and the pressure is 50 psi

PolarNik [594]

Answer:

a) P₂ = 3219.11 lbf / ft² , b) P₂ = 721.91 lbf / ft² , c) P₂ = 5707.31 lbf / ft²

Explanation:

For this exercise we can use the fluid mechanics equations, let's start with the continuity equation, index 1 is for the starting point and index 2 for the end point of the reduction

A₁ v₁ = A₂ v₂

v₂ = v₁ A₁ / A₂

The area of a circle is

A = π r² = π/4 d²

v₂ = v₁ (d₁ / d₂)²

Let's calculate

v₂ = 12 (7/3)²

v₂ = 65 feet / s

Now let's use Bernoulli's equation

P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂

P₁ - P₂ = ρ g (y₂ –y₁) + ½ ρ (v₂² - v₁²)

Case 1. The pipe is horizontal, so

y₁ = y₂

P₁ - P₂ = ½ ρ (v₂² –v₁²)

P₂ = P₁ - ½ ρ (v₂² –v₁²)

ρ = 62.43 lbf / ft³

P₁ = 50 psi (144 lbf/ ft² / psi) = 7200 lbf / ft²

P₂ = 7200 - ½ 62.43 / 32 (65² -12²)

P₂ = 7200 - 3980.89

P₂ = 3219.11 lbf / ft²

Case 2 vertical pipe with water flow up

y₂ –y₁ = 40 ft

P₁ - P₂ = ρ g (y₂ –y₁) + ½ rho (v₂² - v₁²)

7200 - P₂ = 62.43 (40) + ½ 62.43 / 32 (65 2 - 12 2) =

P₂ = 7200 - 2497.2 - 3980.89

P₂ = 721.91 lbf / ft²

Case 3. Vertical water pipe flows down

y₂ –y₁ = -40

P₂ = 7200 + 2497.2 - 3980.89

P₂ = 5707.31 lbf / ft²

3 0

3 years ago

Why does my delivery date keep changing on my tesla model 3

telo118 [61]

Because i stole it lol

5 0

3 years ago

Air enters a compressor operating at steady state at 1 atm with a specific enthalpy of

Savatey [412]

Answer:

option C

option A

Explanation:

Enthalpy gained by air= 1023-290

= 733 kJ/kg

Rate of energy gain= mass flow rate × Enthalpy gained by air

= 0.1 × 733

= 73.3 kJ/s

rate of heat transfer between compressor and air= 77kW

Heat loss by air to surroundings= 77-73.3

=3.7kW

Enthalpy lost by steam in turbine= 1407.6-1236.4

= 171.2 Btu/lb

Rate of energy transfer to turbine= Enthalpy lost by steam× mass flow rate

= 171.2×5

= 856 Btu/s

Net rate of energy transfer to turbine=rate of Energy transfer to turbine- rate of heat transfer to turbine

= 856-40

= 816 Btu/s

8 0

4 years ago