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sammy [17]
3 years ago
9

What is the empirical formula of a substance that contains 12.0 g of c, 2.00 g of h, and 5.33 g of o?

Chemistry
1 answer:
QveST [7]3 years ago
8 0
Empirical formula is the simplest ratio of whole numbers of components making up a compound. 
empirical formula can be calculated as follows
                      C                             H                          O
mass          12.0 g                      2.00 g                   5.33 g 
number of moles  
                  12.0 g / 12 g/mol    2.00 g / 1 g/mol       5.33 g / 16 g/mol 
                    = 1.00 mol                = 2.00 mol           = 0.333 mol
divide by the least number of moles
                   1.00 / 0.333              2.00 / 0.333          0.333/ 0.333 
                    = 3.00                     = 6.01                    = 1.00
the number of atoms 
C - 3
H - 6
O - 1
empirical formula is C₃H₆O     
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Answer:

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Explanation:

<em>A chemist determines by measurements that 0.020 moles of nitrogen gas participate in a chemical reaction. Calculate the mass of nitrogen gas that participates.</em>

Step 1: Given data

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Step 2: Calculate the molar mass (M) of nitrogen gas

Molecular nitrogen is a gas formed by diatomic molecules, whose chemical formula is N₂. Its molar mass is:

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Step 3: Calculate the mass (m) corresponding to 0 0.020 moles of nitrogen gas

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m = n × M

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