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sammy [17]
3 years ago
9

What is the empirical formula of a substance that contains 12.0 g of c, 2.00 g of h, and 5.33 g of o?

Chemistry
1 answer:
QveST [7]3 years ago
8 0
Empirical formula is the simplest ratio of whole numbers of components making up a compound. 
empirical formula can be calculated as follows
                      C                             H                          O
mass          12.0 g                      2.00 g                   5.33 g 
number of moles  
                  12.0 g / 12 g/mol    2.00 g / 1 g/mol       5.33 g / 16 g/mol 
                    = 1.00 mol                = 2.00 mol           = 0.333 mol
divide by the least number of moles
                   1.00 / 0.333              2.00 / 0.333          0.333/ 0.333 
                    = 3.00                     = 6.01                    = 1.00
the number of atoms 
C - 3
H - 6
O - 1
empirical formula is C₃H₆O     
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what is the electrons, valence electrons, and electron shells number please answer all 3 questions (look at the picture)
MariettaO [177]

In picture one, there are four electrons, one valance electrons and two shells, in image two there are three electrons, one valance electrons and two shells whereas there are 13 electrons, three valance electrons and three shells.

<h3>What is Electrons, Valence Electrons, and Electron Shells Numbers?</h3>

<u>Electrons</u>:

An electron is a negatively charged particle which can be either bounded with to an atom. Electrons belong to the first generation of the lepton particle family, and are generally thought to be elementary particles because they have no known components or substructure.

<u>Valence Electrons:</u>

Valence electrons are those electrons which are present in outermost shell or in valence shell or energy level of an atom. For example, oxygen has six valence electrons, two in the 2s subshell and four in the 2p subshell.

<u>Electron Shells Numbers</u>:

Each shell can contain only a fixed number of electrons: the first shell can hold up to two electrons, the second shell can hold up to eight (2 + 6) electrons, the third shell can hold up to 18 (2 + 6 + 10) and so on.

So we can conclude that In picture one, there are four electrons, one valance electrons and two shells, in image two there are three electrons, one valance electrons and two shells whereas there are 13 electrons, three valance electrons and three shells.

Learn more about Valence Electrons here: brainly.com/question/371590

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4 0
1 year ago
Which would you expect to have higher enthalpy of fusion, N2 or I2? Explain your choice.
r-ruslan [8.4K]
The enthalpy of fusion of a substance is the energy required to change the state of a substance from solid to liquid at a constant temperature. The enthalpy of fusion for iodine, I₂, will be higher. This is because there are stronger intermolecular forces holding the iodine molecules together. The stronger intermolecular forces arise from the fact that iodine is a much larger molecule, so it has much more electrons resulting in higher Van der Waal's forces. This is also visible in the fact that at room temperature, iodine is a solid while nitrogen is a gas.<span />
5 0
3 years ago
How many grams of acetylene are produced by adding 3 moles of cac2
jolli1 [7]

Answer:

78.12g of acetylene

Explanation:

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2 H₂O + CaC₂ → C₂H₂ + Ca(OH)₂

<em>Where 1 mole of C₂H₂ (acetylene) is produced per mole of CaC₂</em>

Thus, the addition of 3 moles of CaC₂ produces 3 moles of acetylene.

As molecular mass of acetylene is 26.04g/mol, grams of acetylene produced are:

3mol C₂H₂ × (26.04g / mol) = <em>78.12g of acetylene</em>

8 0
3 years ago
1. What kinds of metals are REALLY reactive? why?
Olin [163]

Answer:

1. Alkali metals (group 1)

2. halogens (Group 17)

3. noble gasses (group 18)

Explanation:

1. alkali metals only have one valence electron meaning that they really want to lose that one valence electron to get a full octet.

2. halogens have 7 valence electrons meaning that they just need to gain 1 to get a full octet.

3. Nobel gasses already have a full octet meaning that they don't want to react. (atoms only react to get a full octet)

I hope this helps.  Let me know if anything is unclear.

8 0
3 years ago
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seropon [69]

Answer:

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B) Fe(NH3)23 is a low spin complex and this is because the complex is made up of strong field ligands, this strong field ligands makes it possible for paring to take place

note : Ligands in which its donor atoms are ; Nitrogen,phosphorous or carbon are considered strong ligands

3 0
4 years ago
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