Answer:
6.68754...
Step-by-step explanation:
Assuming you mean:

Work problems are solved by first figuring out how much of the job they can do in each hour. Shawn can do 1/4 of the job in an hour and Ellie can do 1/6 of the job in an hour. 1/6+1/4=2/12+3/12=5/12. This means that they can do 5/12 of the job an hour. This means that together they can do the job in 2 2/5 hours. The foreman is obviously wrong because first of all Shawn can do it alone in 4 hours, so with Ellie he will do it faster, and second of all 2 2/5<5. Hope this helped!
<h3>
Answer:</h3>
- y = -(x -3)² +3 . . . . (agrees with your answer)
- see the attachment for a graph
<h3>
Step-by-step explanation:</h3>
Factoring the leading -1 from the first two terms, we have ...
... y = -(x² -6x) -6
Adding 9 inside parentheses to complete the square, then adding the opposite amount outside parentheses, we have ...
... y = -(x² -6x +9) -6 +9
... y = -(x -3)² +3
4 is equal to 2*2 (double the 2 is 4)
Answer:
E(3.75,-2.5)
G(-0.75,-3)
Step-by-step explanation:
Point E is the midpoint of the segment AB, then it has coordinates

Point F is the midpoint of the segment EB, then it has coordinates

Let S be the midpoint of segment CB, then it has coordinates

Point G is the midpoint of segment CS, then its coordinates are
