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3 years ago

In Java please.

Computers and Technology

1 answer:

SSSSS [86.1K]3 years ago

3 0

Explanation:

la verdad es que java es muy estrcita deves entrar al link java y descaragrla de nuevo luego haces eso otra vez y te funcionara

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Attackers craft malicious probe packets and scan for services such as HTTP over SSL (HTTPS), SMTP over SSL (SMPTS) and IMAP over

pentagon [3]

Answer:(d)Scan shows that no scanned port is live on the network

Explanation:

Honeypot shows any attempt of unauthorized access to information in the system. Scan showing not scanned port is live on the network shows the presence of honeypot so that hackers could be trapped to be believed that there are no scanned port.

4 0

3 years ago

What is one potential problem with the following loop? System.out.print("Enter integers. Enter -1 to exit."); System.out.println

iris [78.8K]

Answer:

The answer to this question can be given as

The potential problem with the loop is it's counts when the user enters -1 from the keyboard, so the count will too many.

Explanation:

In the program there some line is missing. So the right program of the question can be given as:

import java.util.*; //import package for take input from user.

public class Main //define main class.

{

public static void main(String[] args)//define main function

{

Scanner scan=new Scanner(System.in); //creating object.

//print values.

System.out.print("Enter integers. Enter -1 to exit.");

System.out.println(" Count of integers entered will be returned.");

int n=0,c=0; //declaring integer variable.

while (n != -1) //loop

{

n = scan.nextInt(); //take input by user and hold on variable n.

c++;

}

System.out.println(c); //print value.

}

output:

Enter integers. Enter -1 to exit. Count of integers entered will be returned.

-1

7 0

4 years ago

Here is the problem specification: An Internet service provider has three different subscription packages for its customers: Pac

Andrej [43]

Answer:

In C++:

#include <iostream>

using namespace std;

int main(){

int hour; char pkg; float bill = 0;

cout<<"Package: "; cin>>pkg;

cout<<"Hour: "; cin>>hour;

if(hour<=744 && hour >=0){

switch (pkg) {

case 'A':

bill = hour * 9.95;

if(hour >10){bill = 10 * 9.95 + (hour - 10) * 2;}

break;

case 'B':

bill = hour * 14.5;

if(hour >10){bill = 20 * 14.5 + (hour - 20) * 1;}

break;

case 'C':

bill = 19.95;

break;

default:

cout << "Package must be A, B or C";}

cout<<"Total Bills: $"<<bill; }

else{ cout<<"Hour must be 0 - 744"; }

return 0;

}

Explanation:

This declares all variables: int hour; char pkg; float bill=0;

This prompts the user for package type: cout<<"Package: "; cin>>pkg;

This prompts the user for number of hours: cout<<"Hour: "; cin>>hour;

This checks if hour is between 0 and 744 (inclusive)

if(hour<=744 && hour >=0){

If true, the following is executed

A switch statement to check valid input for package

switch (pkg) {

For 'A' package

case 'A':

Calculate the bill

bill = hour * 9.95;

if(hour >10){bill = 10 * 9.95 + (hour - 10) * 2;}

End of A package: break;

For 'B' package

case 'B':

Calculate the bill

bill = hour * 14.5;

if(hour >10){bill = 20 * 14.5 + (hour - 20) * 1;}

End of B package: break;

For C package

case 'C':

Calculate bill: bill = 19.95;

End of C package: break;

If package is not A, or B or C

default:

Prompt the user for valid package cout << "Package must be A, B or C";}

Print total bills: cout<<"Total Bills: $"<<bill; }

If hour is not 0 to 744: else{ cout<<"Hour must be 0 - 744"; }

6 0

3 years ago

2(x-5)-3(3-x)=1/2(x-2)

lana [24]

you distribute and then combine like terms. x=4 :))

4 0

3 years ago

6. Write a C++ program to print the largest three elements in an array.

jasenka [17]

Answer:

if (arr[i] > max) -> max3 = max2, max2 = max , max = arr[i]. else if (arr[i] > max2) -> max3 = max2, max2 = arr[i]. else if (arr[i] > max3) -> max3 = arr[i]. At the end of the loop, we will print all three values.

7 0

2 years ago