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ipn [44]
3 years ago
11

What is the simplified form of the fourth root of x squared times the fourth root of x squared?

Mathematics
2 answers:
Advocard [28]3 years ago
5 0
So, to do this, you would multiply inside the radicals. The answer would be the fourth root of x^4, or x. 
goblinko [34]3 years ago
3 0

Answer:

simplified form of the expression is x

Step-by-step explanation:

As per statement of the question the expression is

(4\sqrt{x^{2}}) × (4\sqrt{x^{2} })

we can rewrite the expression as (x^{2})^{\frac{1}{4} } (x^{2})^{\frac{1}{4} }

(x^{2})^{\frac{1}{4}}(x^{2})^{\frac{1}{4}} =(x^{2})^{(\frac{1}{4}+\frac{1}{4})} [since (x^{a} )(x^{b}) =x^{a+b} ]

=(x^{2} )^{\frac{2}{4} }

=(x^{2} )^{\frac{1}{2} } [Since (a^{b})^{c} =a^{(b)(c)} ]

= x

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Which animal shelter has the dog that weighs the greatest?
Marizza181 [45]
Do you have a picture?
7 0
3 years ago
Represent the geometric series using the explicit formula.
Dennis_Churaev [7]

The correct answer is:

b.) f(n) = 3 • (-2)^(n-1)

Further explanation:

Given sequence is:

3, -6, 12, -24, ...

We have to find the common ratio first.

Common ratio is the ratio between two consecutive terms of a geometric sequence.

It is denoted by r.

So,

Here,\\a_1=3\\a_2=-6\\a_3=12\\a_4=-24\\r=\frac{a_2}{a_1}=\frac{-6}{3}=-2\\\frac{a_3}{a_2}=\frac{12}{-6}=-2

General formula for geometric sequence is:

a_n=a_1r^{n-1}\\Here\\a_n\ is\ the\ nth\ term\\a_1\ is\ the\ first\ term\\and\\r\ is\ common\ ratio

Putting the values of a1 and r

a_n=3.(-2)^{n-1}\\f(n)=3.(-2)^{n-1}

Hence,

The correct answer is:

b.) f(n) = 3 • (-2)^(n-1)

Keywords: Geometric Sequence, Explicit formula

Learn more about geometric sequence at:

  • brainly.com/question/2048256
  • brainly.com/question/2115122

#LearnwithBrainly

7 0
3 years ago
4^2-6(2^x)-16=0<br><br><br>solve for x
ahrayia [7]
Assuming that   <span>4^2-6(2^x)-16=0   is correct, we can rearrange it as:

</span><span>-6(2^x) + 4^2 - 16=0

Are you sure it's not   </span>6(2^x) + 4^2 - 16=0  ?

If   6(2^x) + 4^2 - 16=0    is correct, then

6(2^x) + 4^2 - 16=16 - 16 = 0, that is,   6(2^x) = 0.  Then x = 0 (answer)
8 0
3 years ago
How do I solve this ?
noname [10]
The answer is around 29
8 0
3 years ago
.3x+.03x+.003x+.0003x+.00003x=3<br> solve for x
Lemur [1.5K]
First, you can combine all of the terms involving x:
0.3x + 0.03x + 0.003x + 0.0003x + 0.00003x = 3
0.33333x = 3
0.33333x / 0.33333 = 3 / 0.33333
x = 9.0000900009…
x ≈ 9
Hope this helps! :)

3 0
3 years ago
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