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faltersainse [42]
3 years ago
12

Select the correct answer from each drop-down menu. How are real gases different from ideal gases? Real gases differ from ideal

gases because in a real gas, and .
Chemistry
2 answers:
lawyer [7]3 years ago
8 0

They have a mass for the particles

There are no totally elastic collisions

There are intermolecular forces

ololo11 [35]3 years ago
6 0

1. Particles take up some volume

2. Intermolecular forces between particles

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Toxicants generally follow the laws of ________, moving from areas of high concentration to areas of lower concentration
zloy xaker [14]

Toxicants generally follow the Law of Diffusion , moving from areas of high concentration to areas of lower concentration.

<h3><u>What are Toxicants ?</u></h3>

Any hazardous chemical is a toxicant. Both naturally occurring and artificial toxicants have the potential to be harmful. A toxin, in contrast, is a poison created spontaneously by an organism (e.g. plant, animal, insect). The many toxicant categories may be present in the air, land, water, or food.

A substance is toxic if it has the potential to be harmful or have negative effects on health. Chemicals like polychlorinated biphenyls (PCBs) and dioxin, which are present at some hazardous waste sites, often cause people to worry.

<h3><u>What is the Law of Diffusion ?</u></h3>

Graham's law of diffusion states that the ratio of the diffusion rate of two gases is the same as the ratio of the square root of the molar mass of the gases.

To view more questions about Toxicants, refer to: brainly.com/question/5896648

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8 0
1 year ago
Only positive ions have a charge. true or false?
Elis [28]

Answer:

true

Explanation:

5 0
3 years ago
Calculate the Molarity of a 750ml Solution in which 26 grams of sodium chloride (NaCl) are dissolved​
enot [183]

Answer:0.59M

Explanation:

8 0
3 years ago
A concentration cell is constructed using two Ni electrodes with Ni2+ concentrations of 1.0 M and 1.00 � 10�4 M in the two half-
Komok [63]

<u>Answer:</u> The cell potential of the cell is +0.118 V

<u>Explanation:</u>

The half reactions for the cell is:

<u>Oxidation half reaction (anode):</u>  Ni(s)\rightarrow Ni^{2+}+2e^-

<u>Reduction half reaction (cathode):</u>  Ni^{2+}+2e^-\rightarrow Ni(s)

In this case, the cathode and anode both are same. So, E^o_{cell} will be equal to zero.

To calculate cell potential of the cell, we use the equation given by Nernst, which is:

E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Ni^{2+}_{diluted}]}{[Ni^{2+}_{concentrated}]}

where,

n = number of electrons in oxidation-reduction reaction = 2

E_{cell} = ?

[Ni^{2+}_{diluted}] = 1.00\times 10^{-4}M

[Ni^{2+}_{concentrated}] = 1.0 M

Putting values in above equation, we get:

E_{cell}=0-\frac{0.0592}{2}\log \frac{1.00\times 10^{-4}M}{1.0M}

E_{cell}=0.118V

Hence, the cell potential of the cell is +0.118 V

5 0
3 years ago
Solve for x, where M is molar and s is seconds. x=(5.3×103M−2s−1)(0.26M)3
GREYUIT [131]

Answer:

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