2Ca + O2 = 2CaO
First, determine which is the excess reactant
72.5 g Ca (1 mol) =1.8089725036
(40.078 g)
65 g O2 (1 mol) =2.0313769611
(15.999g × 2)
Since the ratio of to O2 is 2:1 in the balanced reaction, divide Ca's molar mass by 2 to get 0.9044862518. this isn't necessary because Ca is already obviously the limiting reactant. therefore, O2 is the excess reactant.
Now do the stoichiometry
72.5 g Ca (1 mol Ca) (1 mol O2)
(40.078 g Ca)(2 mol Ca)(31.998g O2)
=0.0282669621 g of O2 left over
Answer: i believe it was convection
Explanation: it is convection im pretty sure
Answer:
Explanation:
The answer is C Enthaply and entropy because temperature plays a big role in reactions
Answer:
Hey, I'll help but I don't know what your options are.
Explanation:
Answer:
8.194 Mev per nucleon
Explanation:
Mass of Barium = 135.905 amu
number of proton = 56, number of neutron = 80
Md = (Mp + Mn) - Mb Mp is the mass of proton, Mn is the mass of neutron, Mb is the mass of barium and Md is the mass defect
Mn = 1.00867 amu Mp = 1.00728 amu
Md = ( 56 ( 1.00728) + 80 ( 1.00867) = 137.1013 - 135.905 =1.1963 amu
Md = 1.1963 × 1 ÷ ( 6.02214 × 10 ²⁶ amu ) = 1.9865 × 10 ⁻²⁷ kg
Energy = mc² = 1.9865 × 10 ⁻²⁷ kg × (2.99792 × 10 ⁸ m/s)²
E= 1.78537 × 10⁻¹⁰ J
to convert to Mev
1.78537 × 10⁻¹⁰ × 6241457006000 = 1114.33 Mev
binding energy per nucleon = 1114.33 / 136 =8.194 Mev per nucleon
