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Degger [83]
2 years ago
11

Solve for x, where M is molar and s is seconds. x=(5.3×103M−2s−1)(0.26M)3

Chemistry
1 answer:
GREYUIT [131]2 years ago
4 0

Answer:

guys can u solve my ques plz

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When small pieces of manganese oxide were added to a solution of hydrogen peroxide, water and oxygen were produced. Manganese ox
Evgesh-ka [11]

The change which increase the rate of the reaction is by increasing the amount of solution.

<h3>What is the rate of the reaction?</h3>

Rate of the reaction gives idea about the speed of the completion of the reaction or the formation of the products.

Given chemical reaction is:
2H₂O₂ \overset{MnO_{2}}{\rightarrow} 2H₂O + O₂

In the above chemical reaction MnO₂ acts as a catalyst which helps in increasing the rate of the reaction without being involved in the reaction. So the formation of the product depends only on the concentration of the solution. So, by increasing the solution amount will increase in the rate.

Hence, increasing the amount of solution will increase the rate.

To know more about rate of reaction, visit the below link:
brainly.com/question/7578129

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1 year ago
Balance this chemical equation. Choose "blank" for the box if no other coefficient is needed. Writing the symbol implies "1."
DENIUS [597]

Answer: 3NH_4OH+AlCl_3\rightarrow Al(OH)_3+3NH_4Cl

Explanation: A double displacement reaction is one in which exchange of ions take place.

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

3NH_4OH+AlCl_3\rightarrow Al(OH)_3+3NH_4Cl

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2 years ago
In what state of matter are the particles vibrating at high speeds?
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The answer would be C
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Based on its location on the periodic table, which element would be most likely to form a negative ion?
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<span>Fluorine ONLY form\s an ion with a -1 charge. The other three are metals, and metals for positively charged ions.</span>
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